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April 24th, 2017, 04:11 PM   #1
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quadratic formula...But this time I should be getting Decimal

I tried to solve b, but guessing I got it wrong as I did not get a decimal?

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Last edited by skipjack; April 25th, 2017 at 12:26 AM.
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April 24th, 2017, 05:25 PM   #2
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How are you simplifying $x=\frac{1\pm\sqrt{29}}{2}$ (which should be your final answer)?
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April 24th, 2017, 05:27 PM   #3
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how you went from

$x=\dfrac{1\pm\sqrt{29}}{2}$

to

$x =15 \text{ or }x=14$

will be fascinating to hear

that $29$ is under a square root sign.
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April 24th, 2017, 05:56 PM   #4
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Quote:
Originally Posted by romsek View Post
how you went from

$x=\dfrac{1\pm\sqrt{29}}{2}$

to

$x =15 \text{ or }x=14$

will be fascinating to hear

that $29$ is under a square root sign.
To me, it looks like the "ignore the radical" method ...
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April 24th, 2017, 05:59 PM   #5
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To me, it looks like the "ignore the radical" method ...
that's the second time I've fallen for that this week 99
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April 24th, 2017, 06:32 PM   #6
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Quote:
Originally Posted by greg1313 View Post
How are you simplifying $x=\frac{1\pm\sqrt{29}}{2}$ (which should be your final answer)?
Okay thanks so no decimal this time...
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April 24th, 2017, 06:35 PM   #7
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Quote:
Originally Posted by romsek View Post
how you went from

$x=\dfrac{1\pm\sqrt{29}}{2}$

to

$x =15 \text{ or }x=14$

will be fascinating to hear

that $29$ is under a square root sign.
Hmm okay, I guess because the line that makes me think division...plus if we are to add and - the 1 then wouldn't 29 plus equal 30 and minus 1 equal 28?
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April 24th, 2017, 06:38 PM   #8
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Quote:
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To me, it looks like the "ignore the radical" method ...
So when do we divide? Do we only divide the numbers if any outside the radical if that's the square root sign?
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April 24th, 2017, 07:10 PM   #9
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In exact form, the expression, $\dfrac{1 \pm \sqrt{29}}{2}$, is as simplified as it can be.

Entered into a calculator, see attachment ...
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April 24th, 2017, 07:34 PM   #10
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In exact form, the expression, $\dfrac{1 \pm \sqrt{29}}{2}$, is as simplified as it can be.

Entered into a calculator, see attachment ...
Hmm, okay thanks for the additional help.
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