My Math Forum quadratic formula...But this time I should be getting Decimal

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April 24th, 2017, 04:11 PM   #1
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quadratic formula...But this time I should be getting Decimal

I tried to solve b, but guessing I got it wrong as I did not get a decimal?

Thanks
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Last edited by skipjack; April 25th, 2017 at 12:26 AM.

 April 24th, 2017, 05:25 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,950 Thanks: 1141 Math Focus: Elementary mathematics and beyond How are you simplifying $x=\frac{1\pm\sqrt{29}}{2}$ (which should be your final answer)? Thanks from topsquark
 April 24th, 2017, 05:27 PM #3 Senior Member     Joined: Sep 2015 From: USA Posts: 2,496 Thanks: 1371 how you went from $x=\dfrac{1\pm\sqrt{29}}{2}$ to $x =15 \text{ or }x=14$ will be fascinating to hear that $29$ is under a square root sign. Thanks from topsquark
April 24th, 2017, 05:56 PM   #4
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Quote:
 Originally Posted by romsek how you went from $x=\dfrac{1\pm\sqrt{29}}{2}$ to $x =15 \text{ or }x=14$ will be fascinating to hear that $29$ is under a square root sign.
To me, it looks like the "ignore the radical" method ...

April 24th, 2017, 05:59 PM   #5
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Quote:
 Originally Posted by skeeter To me, it looks like the "ignore the radical" method ...
that's the second time I've fallen for that this week 99

April 24th, 2017, 06:32 PM   #6
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Quote:
 Originally Posted by greg1313 How are you simplifying $x=\frac{1\pm\sqrt{29}}{2}$ (which should be your final answer)?
Okay thanks so no decimal this time...

April 24th, 2017, 06:35 PM   #7
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Quote:
 Originally Posted by romsek how you went from $x=\dfrac{1\pm\sqrt{29}}{2}$ to $x =15 \text{ or }x=14$ will be fascinating to hear that $29$ is under a square root sign.
Hmm okay, I guess because the line that makes me think division...plus if we are to add and - the 1 then wouldn't 29 plus equal 30 and minus 1 equal 28?

April 24th, 2017, 06:38 PM   #8
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Quote:
 Originally Posted by skeeter To me, it looks like the "ignore the radical" method ...
So when do we divide? Do we only divide the numbers if any outside the radical if that's the square root sign?

April 24th, 2017, 07:10 PM   #9
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In exact form, the expression, $\dfrac{1 \pm \sqrt{29}}{2}$, is as simplified as it can be.

Entered into a calculator, see attachment ...
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April 24th, 2017, 07:34 PM   #10
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Quote:
 Originally Posted by skeeter In exact form, the expression, $\dfrac{1 \pm \sqrt{29}}{2}$, is as simplified as it can be. Entered into a calculator, see attachment ...
Hmm, okay thanks for the additional help.

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