My Math Forum I need help dividing a line into unequal segments!
 User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 April 20th, 2017, 09:35 AM #11 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,788 Thanks: 1037 Math Focus: Elementary mathematics and beyond What kind of instrument are you building?
April 20th, 2017, 10:58 AM   #12
Newbie

Joined: Apr 2017
From: Seattle

Posts: 14
Thanks: 1

Quote:
 Originally Posted by ronmryd It's for a harp, not a fretted instrument.
Been being built for hundreds of years without my interference. But I want precision!

Nice with the Roll The Bones avatar BTW.

April 20th, 2017, 10:34 PM   #13
Senior Member

Joined: Feb 2016
From: Australia

Posts: 1,579
Thanks: 541

Math Focus: Yet to find out.
Quote:
 Originally Posted by ronmryd It's for a harp, not a fretted instrument. Thanks though.
I don't understand. Fretted or not, you essentially want a line divided into 33 sections, with each section getting smaller and smaller as you progress away from one end (or bigger and bigger from the other end). That to me is the same thing.

The website allows you to put your own scaling length in, and the number of frets, or in your case, 33.

 April 21st, 2017, 05:34 AM #14 Newbie   Joined: Apr 2017 From: Seattle Posts: 14 Thanks: 1 I tried their calculator and if only I could set the first and last segments lengths to what I need them to be I would be all set. I can make an excel spreadsheet spit out 35 declinating numbers starting at 1.18 but not with the last one being .88 If no one has a ready solution could anyone point me in a direction to explore instead? Some keywords for a certain type of math discipline to explore? If it's not algebra then perhaps a different sub forum would be appropriate. If it's unsolvable do I qualify for some million dollar math x-prize? Thanks again.
 April 21st, 2017, 07:39 AM #15 Newbie   Joined: Apr 2017 From: Seattle Posts: 14 Thanks: 1 What about a divergent series (not by Veronica Roth) in Calculus? Trying to solve it with triangular numbers doesn't work for this.
 April 21st, 2017, 09:00 AM #16 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,128 Thanks: 801 Well, I simply can't see why you don't use ye olde geometric series formula. With 1st = 118 and 35th = 88, then: common ratio = r = .991409236551.... And the result is: 1: 118.000 2: 116.986 3: 115.981 4: 114.985 ... 33: 89.532 34: 88.763 35: 88.000
 April 21st, 2017, 09:52 AM #17 Newbie   Joined: Apr 2017 From: Seattle Posts: 14 Thanks: 1 Denis - A quick question: Does the sum of the results add up to 33.3? If so then I am forever in your debt and all the other math peoples are shamed!
April 21st, 2017, 10:51 AM   #18
Math Team

Joined: Oct 2011
From: Ottawa Ontario, Canada

Posts: 12,128
Thanks: 801

Quote:
 Originally Posted by ronmryd Denis - A quick question: Does the sum of the results add up to 33.3? If so then I am forever in your debt and all the other math peoples are shamed!
Huh? The "results" bring 118 down to 88, so add up to 30.
No matter how exotic the calculations are, 118-88 = 30.
Perhaps someone else here will "see" whadda heck you're
doing...so I remain shamed...

 April 21st, 2017, 11:19 AM #19 Newbie   Joined: Apr 2017 From: Seattle Posts: 14 Thanks: 1 I didn't mean to imply anything rude! When I use the geometric sequence with common ratio=.991409236551 and first=1.18 the total sum of the first 35 terms comes out to 35.801 To use the geometric sequence as a solution I would need to be able to the sum, the first first term, the 35th term, and the number of terms. I don't think there is a way to algebra-cadabra the geometric sequence equation so I can input my requirements and have it work. I apologize to everyone if I haven't been clear in my requirements for this project. I don't know all of the correct keywords of math-ese to explain myself I guess. Until some mentions an idea like "geometric sequence" then I can go look it up and explore it further. Perhaps it's just me but I intuitively feel like there is a simple solution that I just don't have the tools for. I can hunt and peck a solution in the CAD program but that doesn't help me next time or allow me to easily adjust the design if one of my constraints changes. Last edited by ronmryd; April 21st, 2017 at 11:22 AM.
 April 21st, 2017, 01:10 PM #20 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,128 Thanks: 801 Yes, they do add up to ~35.801 Seems like what you're after is something like 2+3=5, but you want 2+3=4.9, and need a way to change 3 to 2.9 (35.801 to 33.3).

 Tags dividing, line, segments, unequal

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post ronmryd New Users 0 April 19th, 2017 01:11 PM nomad609 Calculus 0 October 23rd, 2016 11:39 AM master555 Applied Math 0 December 2nd, 2011 05:56 PM andoxx Algebra 7 February 8th, 2011 08:09 PM Cheesy74 Algebra 4 November 17th, 2009 05:23 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top