April 19th, 2017, 12:48 AM  #1 
Senior Member Joined: Aug 2011 Posts: 483 Thanks: 2  Computing Average of Surds.
Can we compute average of Surds? Example  2√3,4√5,3√2,5√4,6√7,8√3,9√2 Thanks & Regards, Prashant S Akerkar 
April 19th, 2017, 12:51 AM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,105 Thanks: 368 Math Focus: Yet to find out. 
$Avg = \dfrac{2√3 + 4√5 + 3√2 + 5√4 + 6√7 + 8√3 + 9√2}{7}$

April 19th, 2017, 04:15 AM  #3 
Senior Member Joined: May 2016 From: USA Posts: 593 Thanks: 251 
Surds are just numbers so of course we can calculate an average of them. Silly question.

April 19th, 2017, 04:25 AM  #4 
Senior Member Joined: Mar 2015 From: New Jersey Posts: 1,009 Thanks: 83 
It's not a silly question. It's about combining surds. You can add like surds but not unlike surds.

April 19th, 2017, 07:13 AM  #5 
Senior Member Joined: May 2016 From: USA Posts: 593 Thanks: 251  That is plain wrong. $\sqrt{7} + \sqrt{7} = 2\sqrt{7}.$ Is that an exact answer? $\sqrt{2} + \sqrt{5} = \sqrt{2} + \sqrt{5}.$ Then that too is an exact answer. If you object that the second is not exact because it cannot be expressed exactly in decimals, then express the first exactly in decimals. Silly questions invite even sillier responses. 
April 19th, 2017, 09:41 AM  #6 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,475 Thanks: 886 Math Focus: Elementary mathematics and beyond  prashantakerkar, I fear you are not being taken seriously. Do you have any idea why that might be?

April 19th, 2017, 09:53 AM  #7 
Senior Member Joined: Aug 2011 Posts: 483 Thanks: 2 
Thanks. How we can further simplify to get the average of seven numbers which are Surds? What's the answer for the above? Thanks & Regards, Prashant S Akerkar 
April 19th, 2017, 09:59 AM  #8  
Senior Member Joined: May 2016 From: USA Posts: 593 Thanks: 251  Quote:
Do you understand that decimal notation cannot express exactly all real numbers? Last edited by JeffM1; April 19th, 2017 at 10:02 AM.  
April 19th, 2017, 10:19 AM  #9 
Senior Member Joined: Aug 2012 Posts: 1,254 Thanks: 293  
April 19th, 2017, 11:09 AM  #10 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,063 Thanks: 621  

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