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April 17th, 2017, 03:48 PM  #1 
Senior Member Joined: Feb 2016 From: seattle Posts: 370 Thanks: 10  The distance d in miles that a person can see on a clear day from height h is .......
The distance d in miles that a person can see on a clear day from height h is given by d=g (h)=1.22 sq root h For b would I now replace 20320 with any numbers? Thanks 
April 17th, 2017, 05:34 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,656 Thanks: 1327 
Answer the question first, then evaluate for values of h > 20320 ... keep it reasonable since h is in ft.

April 17th, 2017, 05:47 PM  #3 
Senior Member Joined: Feb 2016 From: seattle Posts: 370 Thanks: 10  Thanks, well I would think it decreases since we keep going higher and we keep getting a decimal.but since they already started so high up so maybe I should only go up by one foot to 5 feet each time?

April 17th, 2017, 06:03 PM  #4 
Math Team Joined: Jul 2011 From: Texas Posts: 2,656 Thanks: 1327 
(1) if you were flying in an airplane, could you see a farther horizontal distance by climbing or descending? (2) small changes in units won't change $d$ by much ... try increasing by a few thousand feet of change for each input. 
April 17th, 2017, 06:39 PM  #5 
Senior Member Joined: Feb 2016 From: seattle Posts: 370 Thanks: 10  
April 17th, 2017, 06:45 PM  #6 
Senior Member Joined: Feb 2016 From: seattle Posts: 370 Thanks: 10 
Could someone tell me how to do C ? Or what I could look up on youtube to learn how to do it? it looks like possibly my teacher used division? Thanks!! 
April 17th, 2017, 07:17 PM  #7 
Math Team Joined: Jul 2011 From: Texas Posts: 2,656 Thanks: 1327 
$d=1.22\sqrt{h} \implies h = \left(\dfrac{d}{1.22}\right)^2$ sub in 100 for $d$ ... 

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clear, day, distance, height, miles, person 
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