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April 16th, 2017, 10:28 AM   #1
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Binomial Expansion Help Needed!

I came across a question, which was:

Find the coefficient of c^4d^11 in the expansion of (2c+5d)(c+d)^14.

I can do it easily with the (c+d) bracket, but the (2c+5d) complicates it for me.

Could someone help me out? Thanks a lot!
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April 16th, 2017, 10:33 AM   #2
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is this supposed to be

$[(2c+5d)(c+c)]^{14}$

or

$(2c+5d)(c+d)^{14}$

?
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April 16th, 2017, 10:34 AM   #3
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The latter.
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April 16th, 2017, 10:52 AM   #4
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Quote:
Originally Posted by romsek View Post
$(2c+5d)(c+d)^{14}$
well first expand out the right term

$(2c+5d) \displaystyle \sum_{k=0}^{14} \binom{14}{k} c^k d^{14-k}$

now do the multiplication

$\displaystyle 2\sum_{k=0}^{14}\binom{14}{k} c^{k+1} d^{14-k} +

5\displaystyle \sum_{k=0}^{14}\binom{14}{k} c^k d^{14-k+1}$

grab the $c^4 d^{11}$ coefficents from each sum

$\displaystyle 2 \binom{14}{3} + 5 \binom{14}{4}$

and I leave you to evaluate that last expression
Thanks from agentredlum and arshinmar
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