My Math Forum Reflected line of another line equation

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 April 13th, 2017, 03:45 AM #1 Newbie   Joined: Apr 2017 From: Lithuania Posts: 2 Thanks: 0 Reflected line of another line equation Hey guys, so I need a little bit of help with algebra. I have a task where a line (y1 = mx1 + c) is sent along another line (y2 = mx2 + c) and a ray is reflected (y3 = mx3 + c). I need to find the equation of the reflected line. I only need the final slope and Y-intercept formulas. I've been trying to do this myself but not getting correct results.. I need to find the (y = mx + c) equation. -Thanks!! Last edited by skipjack; April 13th, 2017 at 05:09 AM.
 April 13th, 2017, 05:16 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,373 Thanks: 2010 Are the equations shown those given in the problem?
 April 13th, 2017, 05:35 AM #3 Newbie   Joined: Apr 2017 From: Lithuania Posts: 2 Thanks: 0 Yeah.
 April 13th, 2017, 07:09 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,373 Thanks: 2010 In that case, the line being reflected has a steeper slope than the line it's reflected in, so the reflected ray is on the other side of the line y = 1/2 x - 3/2. The reflection occurs at the point (1, -1) and the reflected ray's equation is y = -x/18 - 17/18 (where x > 1). It would be messy to obtain this result without using trigonometry.

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