March 20th, 2017, 12:49 AM  #1 
Newbie Joined: Mar 2017 From: Tasmania Posts: 25 Thanks: 2  Log graph
Just a little question How would go about graphing 1/log2 to base e? 
March 20th, 2017, 01:07 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 16,595 Thanks: 1199 
That's a constant, whose graph would be a "horizontal" line. Did you intend to ask about graphing a constant?

March 20th, 2017, 03:12 AM  #3 
Newbie Joined: Mar 2017 From: Tasmania Posts: 25 Thanks: 2 
Far out I'm an idiot the function I'm supposed to to be graphing is 1/logx to base 2 :/

March 20th, 2017, 04:12 AM  #4 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 1,884 Thanks: 610 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
No worries. First thing: check that you still remember what $\displaystyle \log_2 x$ means. It means "find the power that when applied to the number 2 gives x". So, if you wanted to calculate $\displaystyle \log_2 8$ the answer to that would be 3 because $\displaystyle 2^3 = 8$. Second thing: when you get a function and you're not sure what it looks like, try putting in some values and seeing what you get, so you get a general idea for how the curve varies. You can choose particular xvalues to try and make your life easier. Because we have a log to base 2, throw in some powers of 2. For example, use xvalues of 0, 1, 2, 4, 8, 16 and then work out the value of the function for each one. What you'll find is that you'll get values for all numbers apart from 0 and 1... Hint: if your calculator gives an error or you get a divide by zero, that usually indicates an asymptote on the curve. 
March 20th, 2017, 08:00 PM  #5 
Newbie Joined: Mar 2017 From: Tasmania Posts: 25 Thanks: 2 
This is a different graph though ben due to it being 1 OVER logx to base 2


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