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March 9th, 2017, 12:07 AM  #1 
Newbie Joined: Feb 2017 From: America Posts: 2 Thanks: 0  Quadratic algebra worded equation
Jenny is y² years old and her daughter Allyson is y years old. If jenny lives to the age of 13y, Allyson will be y² years old. How old is Allyson now? (Note: the difference in ages must remain constant) Thanks, I'm struggling on this question 
March 9th, 2017, 01:04 AM  #2 
Senior Member Joined: Sep 2015 From: CA Posts: 1,199 Thanks: 611 
at present $jp = y^2$ $ap = y$ future $jf = 13y$ $af = y^2$ $jpap = jf  af$ $y^2  y = 13y  y^2$ $2 y^2  14y = 0$ $(2y  14)y = 0$ $2y = 14$ $y = 7$ Allyson is currently $7$ yrs old. Jenny is currently $49$ yrs old. In $42$ yrs Jenny will be $91$ and Allyson will be $49$ 

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algebra, equation, quadratic, worded 
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