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March 8th, 2017, 11:07 PM   #1
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Quadratic algebra worded equation

Jenny is y² years old and her daughter Allyson is y years old. If jenny lives to the age of 13y, Allyson will be y² years old. How old is Allyson now? (Note: the difference in ages must remain constant)

Thanks, I'm struggling on this question
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March 9th, 2017, 12:04 AM   #2
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at present

$jp = y^2$

$ap = y$

future

$jf = 13y$

$af = y^2$

$jp-ap = jf - af$

$y^2 - y = 13y - y^2$

$2 y^2 - 14y = 0$

$(2y - 14)y = 0$

$2y = 14$

$y = 7$

Allyson is currently $7$ yrs old.
Jenny is currently $49$ yrs old.

In $42$ yrs Jenny will be $91$ and Allyson will be $49$
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