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 March 8th, 2017, 11:07 PM #1 Newbie   Joined: Feb 2017 From: America Posts: 2 Thanks: 0 Quadratic algebra worded equation Jenny is y² years old and her daughter Allyson is y years old. If jenny lives to the age of 13y, Allyson will be y² years old. How old is Allyson now? (Note: the difference in ages must remain constant) Thanks, I'm struggling on this question
 March 9th, 2017, 12:04 AM #2 Senior Member     Joined: Sep 2015 From: Southern California, USA Posts: 1,512 Thanks: 761 at present $jp = y^2$ $ap = y$ future $jf = 13y$ $af = y^2$ $jp-ap = jf - af$ $y^2 - y = 13y - y^2$ $2 y^2 - 14y = 0$ $(2y - 14)y = 0$ $2y = 14$ $y = 7$ Allyson is currently $7$ yrs old. Jenny is currently $49$ yrs old. In $42$ yrs Jenny will be $91$ and Allyson will be $49$

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