
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
February 28th, 2017, 12:38 AM  #1 
Newbie Joined: Feb 2017 From: england Posts: 3 Thanks: 0  Can't get the same answer as example
I am trying to follow an example, but I am unable to get the same results. I was under the impression that when you have two numbers next to each other i.e. ai would mean A multiplied by I. = ((65000/10000)1/41)*100 = (6.5 1/4 1)*100 = (1.59671)*100 = 59.67% but I get 1.6250 when I times 6.5 by 1/4 (6.5*0.25 = 1.6250) and I'm unable to get the 1.5967 when I do it. Where am I going wrong? Any help appreciated. Last edited by skipjack; February 28th, 2017 at 04:47 AM. Reason: to add missing opening parenthesis 
February 28th, 2017, 12:52 AM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 850 Thanks: 310 Math Focus: Yet to find out. 
What is the original question exactly? $\displaystyle \left( \left( \dfrac{65000}{10000} \cdot \dfrac{1}{4} \right)  1 \right) * 100 $ ? or $\displaystyle \left( \dfrac{65000}{10000} \cdot \left( \dfrac{1}{4}  1 \right) \right) * 100 $ ? or something else? Don't forget your order of operations (BEDMAS/BODMAS). And pay attention to your brackets! 
February 28th, 2017, 01:32 AM  #3 
Newbie Joined: Feb 2017 From: england Posts: 3 Thanks: 0 
$\displaystyle =((f/s)1/y1)*100$ spoken, it would be f (65000) divided by y (10000) 1/y is meant to be a fraction (1/4). What I'm trying to use is the below method 2 part 4: How to Calculate an Annual Percentage Growth Rate: 7 Steps Last edited by skipjack; February 28th, 2017 at 04:55 AM. 
February 28th, 2017, 04:53 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 16,595 Thanks: 1199 
The $1/y$ should be an exponent: $6.5^{1/4}  1 = 1.5967...  1 = 0.5967$ to 4 decimal places.

February 28th, 2017, 06:06 AM  #5  
Newbie Joined: Feb 2017 From: england Posts: 3 Thanks: 0  Quote:
thank you greatly skipjack for that. Last edited by skipjack; February 28th, 2017 at 07:26 AM.  

Tags 
answer 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
How did they get this answer?  SeanDaniel  Algebra  7  November 27th, 2014 03:17 PM 
Can you answer this?  theturk  Algebra  1  January 25th, 2014 06:21 PM 
Answer No.6  kingkos  Algebra  3  April 13th, 2013 09:14 AM 
Need help with this. Can't get the answer  hamburgertime  Algebra  10  February 17th, 2013 08:32 PM 
numeric entry problem with answer..but I think the answer is  rage  Algebra  2  September 14th, 2012 09:27 PM 