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 February 27th, 2017, 04:41 PM #1 Member   Joined: Mar 2015 From: KY Posts: 35 Thanks: 1 Help with an area problem Having trouble getting this simple one figured out. Can someone help with number 6? Sent from my iPhone using Tapatalk
February 27th, 2017, 04:54 PM   #2
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Math Focus: Yet to find out.
What have you done so far? Have you drawn a picture?

If $x$ is the length, and $x + 1$ is the width, what can be said about the area? i.e., the relationship between length, width and area of a rectangle.
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Last edited by Joppy; February 27th, 2017 at 04:58 PM.

 February 27th, 2017, 05:01 PM #3 Member   Joined: Mar 2015 From: KY Posts: 35 Thanks: 1 Well, I came up with this x(x+1)=72^2 but I can't get worked out from there. Sent from my iPhone using Tapatalk
 February 27th, 2017, 05:18 PM #4 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out. Almost. It's $72ft^2$, not $72^2$. $ft^2$ is the unit of measurement for area. Try with x(x + 1) = 72. Last edited by skipjack; February 28th, 2017 at 07:51 AM.
 February 27th, 2017, 05:18 PM #5 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,064 Thanks: 722 No. x(x + 1) = 72 x^2 + x - 72 = 0 Solve for x.
February 28th, 2017, 07:56 AM   #6
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Quote:
 Originally Posted by scsims Having trouble getting this simple one figured out. Can someone help with number 6? 45b805255a0ce8db9ce90190b8c1b4b6.jpg
One could use algebra, but it's easier to notice that 9*8 = 8*9 = 72.

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