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February 27th, 2017, 04:41 PM  #1 
Member Joined: Mar 2015 From: KY Posts: 35 Thanks: 1  Help with an area problem
Having trouble getting this simple one figured out. Can someone help with number 6? Sent from my iPhone using Tapatalk 
February 27th, 2017, 04:54 PM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out. 
What have you done so far? Have you drawn a picture? If $x$ is the length, and $x + 1$ is the width, what can be said about the area? i.e., the relationship between length, width and area of a rectangle. Last edited by Joppy; February 27th, 2017 at 04:58 PM. 
February 27th, 2017, 05:01 PM  #3 
Member Joined: Mar 2015 From: KY Posts: 35 Thanks: 1 
Well, I came up with this x(x+1)=72^2 but I can't get worked out from there. Sent from my iPhone using Tapatalk 
February 27th, 2017, 05:18 PM  #4 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,453 Thanks: 489 Math Focus: Yet to find out. 
Almost. It's $72ft^2$, not $72^2$. $ft^2$ is the unit of measurement for area. Try with x(x + 1) = 72. Last edited by skipjack; February 28th, 2017 at 07:51 AM. 
February 27th, 2017, 05:18 PM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 11,064 Thanks: 722 
No. x(x + 1) = 72 x^2 + x  72 = 0 Solve for x. 
February 28th, 2017, 07:56 AM  #6  
Global Moderator Joined: Dec 2006 Posts: 18,245 Thanks: 1439  Quote:
 

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