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February 14th, 2017, 11:37 AM  #1 
Newbie Joined: Feb 2017 From: Paraguay Posts: 1 Thanks: 0  how to simplify this formula?
How do you simplify this equation to solve for RPM? 6.089/RPM + 1.98RPM = 14,918 It's part of my new formula for determining peak power RPM by transfer port duration and transfer/boost area. (on a 2 stroke engine) 
February 14th, 2017, 11:57 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 552 
Multiply by rpm. You will get a quadratic equation.

February 14th, 2017, 10:31 PM  #3 
Member Joined: Sep 2016 From: India Posts: 88 Thanks: 30 
First, make it simple by multiplying each term by $1000$ $\dfrac{6089}{\text{RPM}}\;+\;1980\text{RPM}=14918 000$ Now, multiply each term by RPM $6089\;+\;1980\text{RPM}^2=14918\text{RPM}$ $1980\text{RPM}^214918\text{RPM}+6089=0$ We can observe that it's a quadratic equation So, solve it using quadratic formula, i.e., $x=\dfrac{b\pm\sqrt{b^24ac}}{2a}$ 
February 15th, 2017, 03:53 AM  #4 
Math Team Joined: Jul 2011 From: Texas Posts: 3,093 Thanks: 1675  
February 15th, 2017, 07:40 AM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039  

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