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February 10th, 2017, 08:29 AM  #1 
Newbie Joined: Oct 2014 From: In the sea Posts: 15 Thanks: 1  Logarithm function
Hi, If*$\displaystyle log10(b)=1.8*and*loga(b)=2.5752$, what is*a? How does the change of base rule apply here when there are two unknowns a & B ? Thanks, amphi 
February 10th, 2017, 08:54 AM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,692 Thanks: 1351  Quote:
$2.5752 = \dfrac{1.8}{\log_{10}{a}}$ $\log_{10}{a}= \dfrac{1.8}{2.5752}$ $a = 10^{\frac{1.8}{2.5752}}$  
February 27th, 2017, 02:14 PM  #3 
Newbie Joined: Feb 2017 From: Omaha, Nebraska Posts: 8 Thanks: 0 Math Focus: Algebra and Trigonometry  Loagarithms equate to Exponents
Really like Skeeter's solution, but when working with logarithms I get to exponents as soon as possible... log b = 1.8 loga b = 2.5752 logb a = 1/2.5752 b^(1/2.5752) = a 10^(1.8 (1/2.5752)) = a 10^(1.8/2.5752) = a Since logarithms equate to exponents. Last edited by y2kevin; February 27th, 2017 at 02:23 PM. Reason: clearify math. 

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