
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
February 10th, 2017, 07:29 AM  #1 
Newbie Joined: Oct 2014 From: In the sea Posts: 15 Thanks: 1  Logarithm function
Hi, If*$\displaystyle log10(b)=1.8*and*loga(b)=2.5752$, what is*a? How does the change of base rule apply here when there are two unknowns a & B ? Thanks, amphi 
February 10th, 2017, 07:54 AM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,640 Thanks: 1319  Quote:
$2.5752 = \dfrac{1.8}{\log_{10}{a}}$ $\log_{10}{a}= \dfrac{1.8}{2.5752}$ $a = 10^{\frac{1.8}{2.5752}}$  
February 27th, 2017, 01:14 PM  #3 
Newbie Joined: Feb 2017 From: Omaha, Nebraska Posts: 8 Thanks: 0 Math Focus: Algebra and Trigonometry  Loagarithms equate to Exponents
Really like Skeeter's solution, but when working with logarithms I get to exponents as soon as possible... log b = 1.8 loga b = 2.5752 logb a = 1/2.5752 b^(1/2.5752) = a 10^(1.8 (1/2.5752)) = a 10^(1.8/2.5752) = a Since logarithms equate to exponents. Last edited by y2kevin; February 27th, 2017 at 01:23 PM. Reason: clearify math. 

Tags 
function, logarithm 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Deriving y=W[x] (Lambert W (Omega) Function / Product Logarithm)  John Travolski  Calculus  5  May 22nd, 2016 02:45 PM 
Derivative of Logarithm function.  jiasyuen  Calculus  5  January 9th, 2015 09:44 PM 
What is a logarithm function?  supernova1203  Algebra  5  April 19th, 2011 05:18 AM 
Infinitely Nested Logarithm function  karel747  Complex Analysis  8  November 1st, 2010 08:08 PM 
logarithm  s.a.sajib  Applied Math  0  December 31st, 1969 04:00 PM 