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January 20th, 2017, 05:38 PM  #1 
Newbie Joined: Jan 2017 From: ? Posts: 2 Thanks: 0  Pythagoras (Help)
A baseball infield is a square, each side measuring 80m. To the nearest metre what is the distance from home plate to second base? so I did, x = 80msquared + 80msquared = 160 + 160 = 320 then square root 320 which is 17.88854382 to place should I round it too? no idea is it 17.88? Thank You. PS: what is leg length? Last edited by ghira001; January 20th, 2017 at 06:09 PM. Reason: Detailing 
January 20th, 2017, 06:53 PM  #2 
Member Joined: Oct 2016 From: Melbourne Posts: 77 Thanks: 35 
$\displaystyle \begin{align*} 80^2 = 6400 \end{align*}$, not 160...

January 20th, 2017, 08:28 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,178 Thanks: 1646 
The square root of 21800 is 113.1..., which is 113 after rounding.

January 20th, 2017, 08:43 PM  #4 
Senior Member Joined: Aug 2012 Posts: 1,956 Thanks: 547 
Hate to be pedantic at a moment like this, but the distance between the bases is 90 feet. That's 27 point something meters. Not even remotely 80. I know it's irrelevant to the question but still, numbers used in problems should be reasonably accurate if they claim to be about something in the real world. Think how big a baseball field would be if it's 80 meters between the bases. That's 320 meters around, almost a fifth of a mile. https://en.wikipedia.org/wiki/Baseball_field 
January 21st, 2017, 02:05 PM  #5  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,811 Thanks: 724 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
x^2 = 80msquared + 80msquared Then you can take your square root at the end. The reason I mention this is that if the grader can't read it, many mark it wrong. I always drilled my students to write the correct statements. Dan  
January 21st, 2017, 06:10 PM  #6  
Member Joined: Oct 2016 From: Melbourne Posts: 77 Thanks: 35  Quote:
 

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