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January 10th, 2017, 06:25 AM   #1
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6t^(-1/3)-t^(1/3)=5

I need a step by step guide on how to solve for "t".
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January 10th, 2017, 06:47 AM   #2
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The key step is an initial substitution.

Replace $t^{1/3}$ by a new variable, $u$ say.

Then $t^{-1/3}$, is what, in terms of $u$?

After the replacements, solve the new equation for $u$.

Once you have values for $u$, solve $t^{1/3}=u$ for $t$.

VoilĂ !

Last edited by skipjack; January 10th, 2017 at 09:58 AM.
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