My Math Forum Algebra - Year 10 Problem Solving

 Algebra Pre-Algebra and Basic Algebra Math Forum

 January 9th, 2017, 09:31 PM #1 Newbie   Joined: May 2015 From: Australia Posts: 25 Thanks: 5 Algebra - Year 10 Problem Solving Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg? The answer is: 7kg I don't know how to solve this problem. Could someone give me some hints? Last edited by skipjack; January 10th, 2017 at 02:52 AM. January 9th, 2017, 09:52 PM #2 Math Team Joined: Jul 2011 From: Texas Posts: 2,104 Thanks: 979 Quote:  Originally Posted by pianist Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg? The answer is: 7kg I don't know how to solve this problem. Could someone give me some hints?
13(\$5) + x(\$12) = (13+x)(\$7.45) solve for x, the number of kg of cashews Last edited by skipjack; January 10th, 2017 at 02:52 AM.  January 10th, 2017, 02:44 AM #3 Member Joined: Sep 2016 From: kota Posts: 50 Thanks: 11$13(\$5) + x(\$12) = (13+x)(\$7.45)$ $65+12x=96.85+7.45x$ $12x-7.45x=96.85-65$ $4.55x=31.85$ $x=7kg$

 Tags algebra, problem, solving, year

### solve 7kg 70g 7mg give me a solution please

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Fastsad Algebra 5 January 13th, 2016 02:36 AM kingkos Algebra 2 January 7th, 2014 04:35 PM kingkos Algebra 2 January 6th, 2014 05:08 PM kingkos Algebra 2 January 6th, 2014 05:05 PM Klyka Algebra 6 December 21st, 2008 04:14 PM

 Contact - Home - Forums - Top