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January 9th, 2017, 09:31 PM   #1
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Algebra - Year 10 Problem Solving

Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg?

The answer is: 7kg

I don't know how to solve this problem. Could someone give me some hints?

Last edited by skipjack; January 10th, 2017 at 02:52 AM.
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January 9th, 2017, 09:52 PM   #2
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Quote:
Originally Posted by pianist View Post
Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg?

The answer is: 7kg

I don't know how to solve this problem. Could someone give me some hints?
13(\$5) + x(\$12) = (13+x)(\$7.45)

solve for x, the number of kg of cashews
Thanks from deesuwalka

Last edited by skipjack; January 10th, 2017 at 02:52 AM.
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January 10th, 2017, 02:44 AM   #3
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$13(\$5) + x(\$12) = (13+x)(\$7.45)$

$65+12x=96.85+7.45x$

$12x-7.45x=96.85-65$

$4.55x=31.85$

$x=7kg$
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