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 January 9th, 2017, 08:31 PM #1 Member   Joined: May 2015 From: Australia Posts: 77 Thanks: 7 Algebra - Year 10 Problem Solving Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg? The answer is: 7kg I don't know how to solve this problem. Could someone give me some hints? Last edited by skipjack; January 10th, 2017 at 01:52 AM. January 9th, 2017, 08:52 PM #2 Math Team Joined: Jul 2011 From: Texas Posts: 2,770 Thanks: 1424 Quote:  Originally Posted by pianist Jay has 13kg of almonds costing \$5 per kg. How many kg of cashews costing \$12 per kg should be added to get a mixture of the two nut types which would cost \$7.45 per kg? The answer is: 7kg I don't know how to solve this problem. Could someone give me some hints?
13(\$5) + x(\$12) = (13+x)(\$7.45) solve for x, the number of kg of cashews Last edited by skipjack; January 10th, 2017 at 01:52 AM.  January 10th, 2017, 01:44 AM #3 Member Joined: Sep 2016 From: India Posts: 88 Thanks: 30$13(\$5) + x(\$12) = (13+x)(\$7.45)$ $65+12x=96.85+7.45x$ $12x-7.45x=96.85-65$ $4.55x=31.85$ $x=7kg$

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