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 January 4th, 2017, 07:12 AM #1 Member   Joined: May 2016 From: Ireland Posts: 96 Thanks: 1 equation can someone solve 2000 = 4𝐾^0.75 * L^0.25 where k=3/10 L. i tryed to solve this by adding the powers 2000=4(3/10 L^1) however i get an answer of 5000/3 which is not the correct answer the correct answer is 5000(10/3)^.75
 January 4th, 2017, 07:26 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,879 Thanks: 1087 Math Focus: Elementary mathematics and beyond What variable are you solving for? Are you sure the equation is typed correctly?
January 4th, 2017, 08:12 AM   #3
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Quote:
 Originally Posted by markosheehan ...solve 2000 = 4𝐾^0.75 * L^0.25 where k=3/10 L. i tryed to solve this by adding the powers....
Marko, do not use K and k to represent same variable.

Also, it is basic that adding powers works ONLY this way:
a^x * a^y = a^(x+y)

a^x * b^y does NOT equal (ab)^(x+y)

Is your math teacher drunk half the time?

January 4th, 2017, 10:38 AM   #4
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Quote:
 Originally Posted by markosheehan can someone solve 2000 = 4𝐾^0.75 * L^0.25 where k=3/10 L. i tryed to solve this by adding the powers 2000=4(3/10 L^1) however i get an answer of 5000/3 which is not the correct answer the correct answer is 5000(10/3)^.75

See greg's question.

This looks like a a Cobb-Douglas function.

$2000 = 4 * K^{3/4} * L^{1/4}\ and\ K =0.3L \implies$

$2000 = 4 * \left ( \dfrac{3}{10} * L \right )^{3/4} * L^{1/4} = 4 * \left ( \dfrac{3}{10} \right)^{3/4} * L^{3/4} * L^{1/4} = 4L * \left ( \dfrac{3}{10} \right)^{3/4} \implies$

$L = \dfrac{2000}{4} \div \left ( \dfrac{3}{10} \right)^{3/4} = 500 \div \dfrac{3^{3/4}}{10^{3/4}} = 500 * \dfrac{10^{3/4}}{3^{3/4}} \implies$

$L = 500 * \left ( \dfrac{10}{3} \right )^{3/4}.$

We have no clue where the 5000 came from.

 January 5th, 2017, 05:29 AM #5 Member   Joined: May 2016 From: Ireland Posts: 96 Thanks: 1 thanks for answers and my teacher isnt good

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