My Math Forum find axb
 User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 February 4th, 2013, 05:55 PM #1 Senior Member   Joined: Apr 2012 Posts: 799 Thanks: 1 find axb $\text given :$ $\text log a= 1.02 \text$ $\text b=(0.01)^{(0.01)}\text$ $\text find \,\, a \times \,b$ $\text Ans :10 \text$
 February 4th, 2013, 06:14 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,946 Thanks: 1137 Math Focus: Elementary mathematics and beyond Re: find axb $a\,\cdot\,b\,=\,10^{51/50}\,\cdot\,10^{-1/50}\,=\,10^{51/50-1/50}\,=\,10$
 February 4th, 2013, 06:19 PM #3 Senior Member   Joined: Apr 2012 Posts: 799 Thanks: 1 Re: find axb greg1313 : very good
 February 4th, 2013, 07:21 PM #4 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: find axb Albert: a*b, not axb. Go stand in the corner
February 4th, 2013, 08:13 PM   #5
Math Team

Joined: Dec 2006
From: Lexington, MA

Posts: 3,267
Thanks: 408

Re: find axb

Hello, Albert.Teng!

Quote:
 $\text{Given : }\:\log_{10}a \,=\, 1.02 \;\;\;\;b\,=\,(0.01)^{0.01}$ $\;\;\;\text{Find: }\:a\,\times\,b$

$\log_{10}a \,=\,1.02 \;\;\;\Rightarrow\;\;\;a \,=\,10^{1.02}$

$b \:=\0.01)^{0.01} \:=\: \left(10^{-2}\right)^{0.01} \:=\:10^{-0.2}" />

$\text{Therefore: }\:a\,\times\,b \:=\:10^{1.02}\,\times\,10^{-0.02} \:=\:10^{1.02-0.02} \:=\:10^1 \:=\:10$

February 4th, 2013, 08:33 PM   #6
Senior Member

Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,211
Thanks: 521

Math Focus: Calculus/ODEs
Re: find axb

Quote:
 Originally Posted by Denis Albert: a*b, not axb. Go stand in the corner
Albert used $\times$ not $x$.

So, [color=#0000FF]Denis[/color], I must ask you to don the festive conical headgear, and take your place in the corner. :P

February 5th, 2013, 03:54 AM   #7
Math Team

Joined: Oct 2011
From: Ottawa Ontario, Canada

Posts: 14,597
Thanks: 1038

Re: find axb

Quote:
Originally Posted by MarkFL
Quote:
 Originally Posted by Denis Albert: a*b, not axb. Go stand in the corner
Albert used $\times$ not $x$.

So, [color=#0000FF]Denis[/color], I must ask you to don the festive conical headgear, and take your place in the corner. :P
Right, he used axb, but that means a * x * b; go here, in case you don't have one:
http://www.google.ca/search?q=conical+h ... 24&bih=571

February 5th, 2013, 05:00 AM   #8
Global Moderator

Joined: Oct 2008
From: London, Ontario, Canada - The Forest City

Posts: 7,946
Thanks: 1137

Math Focus: Elementary mathematics and beyond
Re: find axb

I always keep mine handy. It has a spandex lining for added comfort.

[attachment=0:1bf4xjxu]images.jpeg[/attachment:1bf4xjxu]
Attached Images
 images.jpeg (4.4 KB, 107 views)

 February 5th, 2013, 10:16 AM #9 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: find axb

 Tags axb, find

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post kingkos Algebra 5 November 24th, 2012 11:40 PM kevinman Algebra 8 March 8th, 2012 05:53 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top

Copyright © 2019 My Math Forum. All rights reserved.