My Math Forum recurrence relation problem

 Algebra Pre-Algebra and Basic Algebra Math Forum

November 7th, 2016, 05:51 AM   #1
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Joined: Nov 2016
From: Israel

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recurrence relation problem

Hi, I would like to get help with the following recurrence relation problem.
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 November 7th, 2016, 06:03 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,929 Thanks: 2205 $P(k) = P(1)\dfrac{4^{k-1}}{k!}$
 November 7th, 2016, 06:13 AM #3 Newbie   Joined: Nov 2016 From: Israel Posts: 7 Thanks: 0 Thanks, but how is that explicit if the answer contains p(1)?
 November 7th, 2016, 06:19 AM #4 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,157 Thanks: 732 Math Focus: Physics, mathematical modelling, numerical and computational solutions I think the problem requires a boundary condition to be stated (P(1) or P(0)).
 November 7th, 2016, 07:09 AM #5 Global Moderator   Joined: Dec 2006 Posts: 20,929 Thanks: 2205 P(1) can have any value. The formula I gave must also hold for k = 0, so it can be written as $P(k) = P(0)\dfrac{4^k}{k!}$, where P(0) can have any value.

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