My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum

LinkBack Thread Tools Display Modes
November 5th, 2016, 01:57 PM   #1
Joined: Aug 2015
From: Alberta

Posts: 18
Thanks: 0

Find Area of a Quadrant of a Circle.

I'm confused once again.

Circle Circumference of 60cm.

Calculate the area of a Quadrant of that Circle.

So I know a Quadrant is a quarter of a circle.

So I first calculate the area of the circle.

A = Pir^2

3.14 x 30 x 30 = 2826, then I divide by 4 to get quarter = 706.5cm^2

But in my text book it says the answer is...

71.63 cm^2

I just realized that I was looking for a diameter not circumference. My mistake.

I figure it out I just did A = C^2 / 4 pi then divided by 4. All good.

Last edited by skipjack; November 5th, 2016 at 03:32 PM.
jayinwww is offline  
November 5th, 2016, 03:31 PM   #2
Global Moderator
Joined: Dec 2006

Posts: 20,969
Thanks: 2219

The answer should be 71.62 cm² (after rounding to 4 significant figures).
skipjack is offline  
November 25th, 2016, 10:21 PM   #3
Joined: Sep 2016
From: India

Posts: 88
Thanks: 30

Hint- We know circumference $\;\;C=2\pi r$

calculate $r$ from this

Area of a quadrant = Area of quarter of circle $=\dfrac{\pi r^2}{4}$
deesuwalka is offline  

  My Math Forum > High School Math Forum > Algebra

area, circle, find, quadrant

Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
Need help with using horizontal slices to find the area of a quarter-circle leo255 Calculus 4 May 27th, 2014 12:41 AM
Area enclosed by a semi-circle and a quarter circle yeoky Algebra 4 May 3rd, 2014 01:06 AM
find area of two circle nabilkud Algebra 1 October 20th, 2012 10:49 PM
Area of square with convex parts - area of circle gus Algebra 1 April 17th, 2011 04:25 PM
Find radius of circle if its area equals its circumferen youtindia Algebra 5 March 18th, 2011 09:36 AM

Copyright © 2019 My Math Forum. All rights reserved.