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November 4th, 2016, 04:12 PM  #1 
Newbie Joined: Aug 2015 From: Alberta Posts: 18 Thanks: 0  Having trouble with formulas (Equations & Transpositions)
Solve for A b = 1/2h (A + C) My first step is to minus C on both sides so I got b  C = 1/2h A then i flip the 1/2 to 2/1 so it's b  C = 2h A My second step is to divide both sides by 2h.. bc/2h = A But in my text book it says the answer is A = 2b/h  C I don't get it, where did i go wrong? 
November 4th, 2016, 04:38 PM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,982 Thanks: 1575  Quote:
$b = \dfrac{1}{2}h(a+c)$ multiply both sides by 2 ... $2b = h(a+c)$ divide both sides by $h$ ... $\dfrac{2b}{h}=a+c$ subtract $c$ from both sides ... $\dfrac{2b}{h}c=a$  
November 8th, 2016, 12:38 AM  #3 
Member Joined: Sep 2016 From: India Posts: 88 Thanks: 30 
$b=\dfrac{1}{2}h(a+c)$ Use inverse operations and leave $a$ at one side Here, $2$ is being divided, so multiply both sides by $2$ $2b=h(a+c)$ $h$ is being multiplied so divide both sides by $h$ $\dfrac{2b}{h}=(a+c)$ $c$ is being added so subtract $c$ from both sides $\dfrac{2b}{h}c=a$ 

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