 My Math Forum Having trouble with formulas (Equations & Transpositions)
 User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 November 4th, 2016, 04:12 PM #1 Newbie   Joined: Aug 2015 From: Alberta Posts: 18 Thanks: 0 Having trouble with formulas (Equations & Transpositions) Solve for A b = 1/2h (A + C) My first step is to minus C on both sides so I got b - C = 1/2h A then i flip the 1/2 to 2/1 so it's b - C = 2h A My second step is to divide both sides by 2h.. b-c/2h = A But in my text book it says the answer is A = 2b/h - C I don't get it, where did i go wrong? November 4th, 2016, 04:38 PM   #2
Math Team

Joined: Jul 2011
From: Texas

Posts: 3,031
Thanks: 1620

Quote:
 Solve for A b = 1/2h (A + C)
your very first step is incorrect. you cannot subtract $c$ from inside the parentheses.

$b = \dfrac{1}{2}h(a+c)$

multiply both sides by 2 ...

$2b = h(a+c)$

divide both sides by $h$ ...

$\dfrac{2b}{h}=a+c$

subtract $c$ from both sides ...

$\dfrac{2b}{h}-c=a$ November 8th, 2016, 12:38 AM #3 Member   Joined: Sep 2016 From: India Posts: 88 Thanks: 30 $b=\dfrac{1}{2}h(a+c)$ Use inverse operations and leave $a$ at one side- Here, $2$ is being divided, so multiply both sides by $2$ $2b=h(a+c)$ $h$ is being multiplied so divide both sides by $h$ $\dfrac{2b}{h}=(a+c)$ $c$ is being added so subtract $c$ from both sides $\dfrac{2b}{h}-c=a$ Tags equations, formulas, transpositions, trouble Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post WarmCustard Algebra 6 October 18th, 2016 03:48 PM zFADwww7 Advanced Statistics 0 November 14th, 2013 04:25 AM yesiam Applied Math 9 September 21st, 2012 04:10 PM Adrian Algebra 4 February 5th, 2012 01:00 PM prashantakerkar Algebra 5 November 15th, 2011 12:10 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top      