My Math Forum [ASK] Ratio of Workers

 Algebra Pre-Algebra and Basic Algebra Math Forum

 October 15th, 2016, 09:51 AM #11 Senior Member     Joined: Sep 2015 From: USA Posts: 2,590 Thanks: 1434 Oh I see what the problem is.. OP changed the number from 24 to 25 w/o telling anyone. post #2 is correct
 October 15th, 2016, 04:41 PM #12 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry Without telling anyone? I think skipjack's explanation is enough. Now I just need to convert it to the algebraic form.
 October 15th, 2016, 07:53 PM #13 Newbie   Joined: Oct 2016 From: Taiwan Posts: 10 Thanks: 2 To saying easily, we set 1 person can do 1 unit of work in 1 day. We lost 5 days for working, so we lose 5 x 12 = 60 units of work. Those units of work should be completed by those additional people in the days after pause. Therefore, if there are 5 days after pause , we need 60 / 5 = 12 people more. If they're 6 days instead, we need 60 / 6 = 10 people more. I think this may be an more clear way for question.
 October 16th, 2016, 07:20 PM #14 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry So, basically the calculation is $\displaystyle \frac{12\times(35-(24+5)+5)}{6}$?
 October 17th, 2016, 02:16 AM #15 Newbie   Joined: Oct 2016 From: Taiwan Posts: 10 Thanks: 2 Or it would be $\displaystyle \frac{12 \times 5}{35-(24+5)}$
 October 17th, 2016, 07:30 PM #16 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry If I want to state the question in equation form, is it $\displaystyle \frac{12+n}{12}=\frac{35-24}{35-(24+5)}$?
 October 18th, 2016, 01:41 AM #17 Newbie   Joined: Oct 2016 From: Taiwan Posts: 10 Thanks: 2 That's already correct, but in another way of thinking, I would prefer $\displaystyle 12(35-24)=(12+n)[35-(24+5)]$ which is better to understand for me.
 October 18th, 2016, 07:30 PM #18 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry The problem is that this question was taught in the ratio lesson.
 October 19th, 2016, 03:37 AM #19 Newbie   Joined: Oct 2016 From: Taiwan Posts: 10 Thanks: 2 Oh I didn't noticed that. Then the last equation you wrote is correct. Thanks from Monox D. I-Fly

 Tags ratio, workers

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post farismadi Algebra 2 July 21st, 2013 06:19 AM satimis Number Theory 3 December 31st, 1969 04:00 PM farismadi Abstract Algebra 0 December 31st, 1969 04:00 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top