October 13th, 2016, 11:32 AM  #1 
Member Joined: Sep 2016 From: zambia Posts: 31 Thanks: 0  exponents
simplify,expressing the final result without using zero or negative integers as exponents [5^(2n+1)+25^n]/[5^2n+5^(1+n)] 
October 13th, 2016, 02:04 PM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,028 Thanks: 420 
This is NOT abstract algebra. It is elementary algebra. $\dfrac{5^{(2n + 1)} + 25^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + (5^2)^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + 5^{2n}}{5^{2n} + 5^{(1 + n)}}.$ Now what? 
October 13th, 2016, 08:01 PM  #3 
Senior Member Joined: Nov 2010 From: Indonesia Posts: 1,951 Thanks: 132 Math Focus: Trigonometry  

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