October 13th, 2016, 11:32 AM  #1 
Member Joined: Sep 2016 From: zambia Posts: 31 Thanks: 0  exponents
simplify,expressing the final result without using zero or negative integers as exponents [5^(2n+1)+25^n]/[5^2n+5^(1+n)] 
October 13th, 2016, 02:04 PM  #2 
Senior Member Joined: May 2016 From: USA Posts: 785 Thanks: 312 
This is NOT abstract algebra. It is elementary algebra. $\dfrac{5^{(2n + 1)} + 25^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + (5^2)^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + 5^{2n}}{5^{2n} + 5^{(1 + n)}}.$ Now what? 
October 13th, 2016, 08:01 PM  #3 
Senior Member Joined: Nov 2010 From: Indonesia Posts: 1,319 Thanks: 114  

Tags 
exponents 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Exponents Law  Meezus  Algebra  1  October 25th, 2015 09:09 PM 
exponents  euphmorning  Algebra  5  April 29th, 2015 01:13 AM 
Exponents  Aman Verma  Algebra  6  December 28th, 2013 09:55 PM 
exponents  mikeportnoy  Algebra  2  December 10th, 2008 07:14 AM 
exponents  johnny  Algebra  2  August 1st, 2007 03:54 AM 