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October 13th, 2016, 11:32 AM   #1
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exponents

simplify,expressing the final result without using zero or negative integers as exponents

[5^(2n+1)+25^n]/[5^2n+5^(1+n)]
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October 13th, 2016, 02:04 PM   #2
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This is NOT abstract algebra. It is elementary algebra.

$\dfrac{5^{(2n + 1)} + 25^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + (5^2)^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + 5^{2n}}{5^{2n} + 5^{(1 + n)}}.$

Now what?
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October 13th, 2016, 08:01 PM   #3
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Quote:
Originally Posted by JeffM1 View Post
This is NOT abstract algebra. It is elementary algebra.
It is just too abstract for him to comprehend.
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