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 October 13th, 2016, 12:32 PM #1 Member   Joined: Sep 2016 From: zambia Posts: 31 Thanks: 0 exponents simplify,expressing the final result without using zero or negative integers as exponents [5^(2n+1)+25^n]/[5^2n+5^(1+n)]
 October 13th, 2016, 03:04 PM #2 Senior Member   Joined: May 2016 From: USA Posts: 881 Thanks: 353 This is NOT abstract algebra. It is elementary algebra. $\dfrac{5^{(2n + 1)} + 25^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + (5^2)^n}{5^{2n} + 5^{(1 + n)}} = \dfrac{5^{(2n + 1)} + 5^{2n}}{5^{2n} + 5^{(1 + n)}}.$ Now what? Thanks from topsquark
October 13th, 2016, 09:01 PM   #3
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Quote:
 Originally Posted by JeffM1 This is NOT abstract algebra. It is elementary algebra.
It is just too abstract for him to comprehend.

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