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July 9th, 2008, 04:53 PM  #1 
Newbie Joined: Jul 2008 Posts: 1 Thanks: 0  NEED Help Quick
i need quick help to solve these problem i keep running into problems when i check my answer Square root of 3x+1 = 3+ square root of x4 and absolute value of 2x+1 = x1 
July 9th, 2008, 10:15 PM  #2 
Senior Member Joined: May 2008 From: York, UK Posts: 1,300 Thanks: 0  Re: NEED Help Quick
Hi which we rearrange to then square both sides: Then we have so: (x5)=0." /> The two solutions are and (which we can check are both consistent with ) Secondly, can be examined in two separate cases: and If then so This has one solution at but this is not valid since we are looking only at On the other hand, if then so This has one solution at but again this is not valid since we are looking only at So has no solutions. 
July 10th, 2008, 09:15 PM  #3 
Member Joined: Feb 2008 Posts: 89 Thanks: 0  Re: NEED Help Quick
[color=#4000BF]Dear Helpless: 2x + 1 = x  1 is readily solved if you consider the graphs of y1 = 2x + 1 and y2 = x  1. y2 has xintercept at (1, 0), with slope = 1. y1 has xint. at (1/2, 0). Clearly, were there solutions, y2 would intersect the "rightmost" branch of y1 in the first quadrant. Given the aforesaid, however, a moment's reflection indicates that no such intersection exists, i.e., the equation is without solutions. Regards, Rich B.[/color] rmath4u22aol.com 

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