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October 4th, 2016, 10:50 AM   #1
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The length of a rectangle is 3 times the width. Not sure how to set this up?

The length of a rectangle is 3 times the width. If the perimeter is to be less than or equal to 104 meters. What are the possible values for the width?

Not sure I know how to set this formula up?
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October 4th, 2016, 10:54 AM   #2
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C'mon Joe...get off yer ass!

w = width
w + w + 3w + 3w = 104 : let's see yer stuff!
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October 4th, 2016, 11:23 AM   #3
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Quote:
Originally Posted by Denis View Post
C'mon Joe...get off yer ass!

w = width
w + w + 3w + 3w = 104 : let's see yer stuff!
Thanks for your help, but no need to make me feel worse than I do already having to need help or even ask.
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October 4th, 2016, 11:39 AM   #4
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You got it wrong: purpose is not to make you feel bad,
BUT to nudge you into showing HOW FAR YOU GOT with it;
most math help site do not give solutions right off the bat,
but 1st request that you show WHERE you're stuck...
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October 4th, 2016, 11:52 AM   #5
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Quote:
Originally Posted by Denis View Post
You got it wrong: purpose is not to make you feel bad,
BUT to nudge you into showing HOW FAR YOU GOT with it;
most math help site do not give solutions right off the bat,
but 1st request that you show WHERE you're stuck...
That I get, it was the telling me to get off my ass is the part I took as you being rude, but guess that was a nice way of talking for you

I just really hate that this math is so confusing to me at times. I have spent two weeks on trying just to learn one section.

I thought the question was wanting it in a form I had not seen before, but now thanks to you I see that it is not.
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October 4th, 2016, 12:07 PM   #6
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Quote:
Originally Posted by GIjoefan1976 View Post
The length of a rectangle is 3 times the width. If the perimeter is to be less than or equal to 104 meters.
What are the possible values for the width?
Quote:
Originally Posted by Denis View Post
C'mon Joe...get off yer ass!

w = width
w + w + 3w + 3w = 104
The content in the quote box immediately above is a good hint. The perimeter can vary,
then so can the width and the length.

$\displaystyle 0 \ < \ 2(w) \ + \ 2(3w) \ \le \ 104 $


Continue.


.
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Last edited by Math Message Board tutor; October 4th, 2016 at 12:14 PM.
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October 4th, 2016, 12:17 PM   #7
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Originally Posted by Math Message Board tutor View Post
This is a good hint. The perimeter can vary, then so can the width and the length.

$\displaystyle 0 \ < \ 2(w) \ + \ 2(3w) \ \le \ 104 $


Continue.


.

Thanks I was able to finally find one I could solve, it's just the "new signs" are getting me confused, and now the new ways of when to use ( ) and [] (] [)
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October 4th, 2016, 12:30 PM   #8
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Originally Posted by GIjoefan1976 View Post
Thanks I was able to finally find one I could solve, it's just the "new signs"
are getting me confused, and now the new ways of when to use ( ) and [] (] [)
You could write/type this instead:


$\displaystyle 0 \ < \ 2*w \ + \ 2*3w \ \le \ 104$
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October 4th, 2016, 12:49 PM   #9
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Originally Posted by GIjoefan1976 View Post
That I get, it was the telling me to get off my ass is the part I took as you being rude, but guess that was a nice way of talking for you
Geeeshhhh Joe, my own mother used to tell me that!

If you get off your ass(!) and draw a rectangle,
label short side w (then long side = 3w),
you can tell right away that perimeter is 8w...right?
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October 4th, 2016, 01:04 PM   #10
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Quote:
Originally Posted by Denis View Post
Geeeshhhh Joe, my own mother used to tell me that!

If you get off your ass(!) and draw a rectangle,
label short side w (then long side = 3w),
you can tell right away that perimeter is 8w...right?
Awe, okay so it runs in the family. I will remember that in the future if I get help from you again
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