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October 4th, 2016, 02:22 PM   #11
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Good luck Joe.
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October 5th, 2016, 03:30 AM   #12
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Let the width of the rectangle be x.
Then length = 3x (3 times the width)
perimeter of rectangle = 2(width+length)
according to problem perimeter is less than or equal to 104 meters.
$\implies\; 2(x+3x) \leq 104$
$\implies\; 2\times 4x \leq 104$
$\implies 8x\leq 104$
$\implies x\leq \dfrac{104}{8}$
$x \leq 13$
Thus, width of the rectangle is less than or equal to 13 meters and the length is less than equal to 39 meters.
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