My Math Forum The length of a rectangle is 3 times the width. Not sure how to set this up?

 Algebra Pre-Algebra and Basic Algebra Math Forum

 October 4th, 2016, 01:22 PM #11 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,328 Thanks: 1024 Good luck Joe. Thanks from GIjoefan1976
 October 5th, 2016, 02:30 AM #12 Newbie   Joined: Sep 2016 From: kota Posts: 8 Thanks: 4 Let the width of the rectangle be x. Then length = 3x (3 times the width) perimeter of rectangle = 2(width+length) according to problem perimeter is less than or equal to 104 meters. $\implies\; 2(x+3x) \leq 104$ $\implies\; 2\times 4x \leq 104$ $\implies 8x\leq 104$ $\implies x\leq \dfrac{104}{8}$ $x \leq 13$ Thus, width of the rectangle is less than or equal to 13 meters and the length is less than equal to 39 meters. Thanks from GIjoefan1976

 Tags length, rectangle, set, times, width

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post GIjoefan1976 Algebra 2 March 15th, 2016 09:04 AM cherryperry Algebra 3 February 13th, 2016 11:16 AM Monox D. I-Fly Geometry 9 September 15th, 2015 01:51 AM Apple30 Geometry 8 June 24th, 2015 09:18 PM ik2244 Algebra 6 November 16th, 2010 07:08 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top