October 4th, 2016, 02:22 PM  #11 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,955 Thanks: 988 
Good luck Joe.

October 5th, 2016, 03:30 AM  #12 
Newbie Joined: Sep 2016 From: kota Posts: 8 Thanks: 4 
Let the width of the rectangle be x. Then length = 3x (3 times the width) perimeter of rectangle = 2(width+length) according to problem perimeter is less than or equal to 104 meters. $\implies\; 2(x+3x) \leq 104$ $\implies\; 2\times 4x \leq 104$ $\implies 8x\leq 104$ $\implies x\leq \dfrac{104}{8}$ $x \leq 13$ Thus, width of the rectangle is less than or equal to 13 meters and the length is less than equal to 39 meters. 

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length, rectangle, set, times, width 
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