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September 22nd, 2016, 03:26 PM   #1
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promise last one for today, -3+x/3 >= x/5-1

-3+x/3 >= x/5-1


so I thought I would get 5x/15 -3x/15 =2x/15 >= 2


Yet besides that I am getting them all wrong, I don't think this is right because how would I get rid of the 2x/15?
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September 22nd, 2016, 03:43 PM   #2
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Quote:
-3+x/3 >= x/5-1
multiply every term by 15 ...

$-45 + 5x \ge 3x - 15$

finish ...
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September 23rd, 2016, 03:02 PM   #3
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Quote:
Originally Posted by GIjoefan1976 View Post
-3+x/3 >= x/5-1


so I thought I would get 5x/15 -3x/15 =2x/15 >= 2


Yet besides that I am getting them all wrong, I don't think this is right because how would I get rid of the 2x/15?
$\displaystyle \frac{2x}{15}\ge 2\Rightarrow 2x\ge 30\Rightarrow x \ge 15$. I presume the problem was to get an inequality in x.
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October 24th, 2016, 02:12 AM   #4
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$-3+\dfrac{x}{3}\geq\dfrac{x}{5}-1$

Multiply each side by $15$

$\implies-45+5x\geq3x-15$

Separate the like terms,

$\implies 5x-3x\geq45-15$

$\implies 2x\geq30$

$\implies x\geq15$

Last edited by deesuwalka; October 24th, 2016 at 02:18 AM.
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