My Math Forum sorry if this is too easy.

 Algebra Pre-Algebra and Basic Algebra Math Forum

September 20th, 2016, 11:24 AM   #1
Senior Member

Joined: Feb 2016
From: seattle

Posts: 377
Thanks: 10

sorry if this is too easy.

I am trying to retake my math class and I am now in inequality and they want me to find the answer on a number line. I believe I found the answer as x>11/7 but I am clueless after that. Thanks
Attached Images
 math.jpg (15.0 KB, 22 views)

September 20th, 2016, 11:29 AM   #2
Math Team

Joined: Jul 2011
From: Texas

Posts: 2,949
Thanks: 1555

$7x > 11$

$\dfrac{7x}{7} > \dfrac{11}{7}$

$x > \dfrac{11}{7}$
Attached Images
 inequality.jpg (20.4 KB, 4 views)

 September 20th, 2016, 11:36 AM #3 Senior Member   Joined: Feb 2016 From: seattle Posts: 377 Thanks: 10 Hey and thanks again skeeter, so would just counting lines and then including zero be how we could get to 11? or should I be looking at it a different way completely?
 September 20th, 2016, 12:08 PM #4 Math Team     Joined: Jul 2011 From: Texas Posts: 2,949 Thanks: 1555 note that there are 7 divisions between each unit 1 = 7/7 1st mark after 1 = 8/7 2nd mark after 1 = 9/7 3rd mark after 1 = 10/7 4th mark after 1 = 11/7 Thanks from GIjoefan1976

 Tags easy

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post mobel Number Theory 3 June 7th, 2017 05:10 AM las96 Elementary Math 4 July 25th, 2014 08:39 AM Algebra 9 April 13th, 2011 06:34 PM clandarkfire Algebra 5 June 27th, 2010 10:59 AM zoidberg Algebra 2 May 14th, 2009 04:07 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top