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September 1st, 2016, 01:42 AM  #1 
Newbie Joined: Sep 2016 From: England, Cambridge Posts: 2 Thanks: 0  algebra logarithms problem
the question I was reading stated solve the following equation: log(x) + ln (x) = 4. and I got to the stage: log(x) + log(x)/log(e) = 4. but then the answers stated that you should do this next: log x(1 + 1/log(e)) = 4. Can someone explain that for me. 
September 1st, 2016, 01:59 AM  #2 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,157 Thanks: 731 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
Just factorise $\displaystyle \log x$ in the same way you'd factorise $\displaystyle xy + 2x = x(y+2)$

September 1st, 2016, 04:23 AM  #3 
Newbie Joined: Sep 2016 From: England, Cambridge Posts: 2 Thanks: 0 
I get it now. Thanks!!!!!


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