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September 1st, 2016, 01:42 AM   #1
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Unhappy algebra logarithms problem

the question I was reading stated solve the following equation:
log(x) + ln (x) = 4.

and I got to the stage:

log(x) + log(x)/log(e) = 4.

but then the answers stated that you should do this next:

log x(1 + 1/log(e)) = 4.

Can someone explain that for me.
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September 1st, 2016, 01:59 AM   #2
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Just factorise $\displaystyle \log x$ in the same way you'd factorise $\displaystyle xy + 2x = x(y+2)$
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September 1st, 2016, 04:23 AM   #3
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I get it now. Thanks!!!!!
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