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January 28th, 2013, 10:57 AM  #1 
Member Joined: Feb 2012 Posts: 78 Thanks: 0  How do I find the base height of a Tetrahedron?
What I am trying to do is find the volume of a tetrahedron. However, I need the base height of the tetrahedron, which I have no idea how to figure out. I know that the edges of the tetrahedron = 1 and the surface area is 4 times the square root of 3. Any help would be greatly appreciated. 
January 28th, 2013, 11:43 AM  #2  
Senior Member Joined: Feb 2010 Posts: 703 Thanks: 138  Re: How do I find the base height of a Tetrahedron? Quote:
 
January 28th, 2013, 04:09 PM  #3 
Member Joined: Feb 2012 Posts: 78 Thanks: 0  Re: How do I find the base height of a Tetrahedron?
Multiplied by 4 because a tetrahedron has 4 sides. But how do you find its base height?

January 28th, 2013, 05:08 PM  #4  
Senior Member Joined: Feb 2010 Posts: 703 Thanks: 138  Re: How do I find the base height of a Tetrahedron? Quote:
Since the edge of the tetrahedron is s = 1, then the area of one face is There are four faces so multiplying by 4 gives the total surface area equal to . By the way, the height is  
January 29th, 2013, 01:44 AM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,370 Thanks: 2007 
Each face of the tetrahedron has inradius of and altitude of length . Hence the height of the tetrahedron is . 

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