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 August 18th, 2016, 07:01 AM #1 Newbie   Joined: Aug 2016 From: woodstock Posts: 2 Thanks: 0 Dimensional Analysis - what am I doing wrong? I have worked this problem and can't figure out what I am doing wrong. I know what the answer is, know I got it wrong and have a key to how to do it. I just need to know why my method isn't working since what I did makes sense to me. Question: The density of water is one gram per cubic centimeter. What is the density of water in pounds per liter? How I Tried to Solve:1 g/cc 1 oz/28.35g 1 lb/16 oz 1cc/1m^3 1 m^3/264.2 gal 1 gal/3.79L (came up with 2.20 x 10^-6) I have a test tomorrow so if someone could help I would appreciate it.
 August 18th, 2016, 07:20 AM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 3,002 Thanks: 1587 you only need ounces that measure weight, not volume ... there is a difference $\dfrac{1 \, gm}{cm^3} \cdot \dfrac{1 \, oz}{28.35 \, gm} \cdot \dfrac{1 \, lb}{16 \, oz} \cdot \dfrac{1000 \, cm^3}{L} = \dfrac{1000}{(28.35)(16)} \approx 2.2 \, \dfrac{lbs}{L}$ makes sense since 1000 gm = 1 kg, which has a weight of 2.2 lbs Thanks from topsquark and henrymcg

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### the viscosity n of a gas depends on the mass m, the effective diameter d and the mean speed of the molecules v . use dimensional analysis to find an expression for n

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