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January 20th, 2013, 07:55 PM   #1
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Algebra Word Problem

This isn't for an assignment, I am just curious to see it finished, possibly explained a little. This is for my own curiosity. Thanks.

A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 2276 miles required 68 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?
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January 20th, 2013, 08:12 PM   #2
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Re: Algebra Word Problem

Let C be the number of miles driven in the city and H be the number of miles driven on the highway. We have:





Solving both for H and equating, we find:





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January 20th, 2013, 08:13 PM   #3
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Re: Algebra Word Problem

Hello, apparentlynothing!

Quote:
A man bought a car that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway.
A recent trip that covered 2276 miles required 68 gallons of gasoline.
Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?



















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January 21st, 2013, 02:17 AM   #4
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As 68 gallons allow at most 1836 miles to be driven in the city, the extra 440 miles are achieved by using 40 of the gallons for driving on the highway instead of in the city, so that only 28 gallons are used for driving in the city.

Hence the number of miles driven in the city is 28*27 = 756.
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January 21st, 2013, 06:14 PM   #5
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Re: Algebra Word Problem

Thank you both so much!
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