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January 20th, 2013, 07:55 PM  #1 
Newbie Joined: Jan 2013 Posts: 2 Thanks: 0  Algebra Word Problem
This isn't for an assignment, I am just curious to see it finished, possibly explained a little. This is for my own curiosity. Thanks. A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 2276 miles required 68 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city? 
January 20th, 2013, 08:12 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: Algebra Word Problem
Let C be the number of miles driven in the city and H be the number of miles driven on the highway. We have: Solving both for H and equating, we find: 
January 20th, 2013, 08:13 PM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: Algebra Word Problem Hello, apparentlynothing! Quote:
 
January 21st, 2013, 02:17 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 21,036 Thanks: 2274 
As 68 gallons allow at most 1836 miles to be driven in the city, the extra 440 miles are achieved by using 40 of the gallons for driving on the highway instead of in the city, so that only 28 gallons are used for driving in the city. Hence the number of miles driven in the city is 28*27 = 756. 
January 21st, 2013, 06:14 PM  #5 
Newbie Joined: Jan 2013 Posts: 2 Thanks: 0  Re: Algebra Word Problem
Thank you both so much!


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