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June 18th, 2016, 08:25 AM  #1 
Newbie Joined: Jun 2016 From: Maine Posts: 9 Thanks: 1 Math Focus: Enjoyed algebra for its utility  Exponent Property question
How do you get $\displaystyle (a^{n})^{1 \over m}$ as the final product? $\displaystyle a^{n \over m} = (a^{1 \over m})^{n}=(a^{n})^{1 \over m} $ 
June 18th, 2016, 09:01 AM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,816 Thanks: 1460  Quote:
Fairly basic property of multiplication ... where does the confusion lie?  

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