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 June 18th, 2016, 07:25 AM #1 Newbie   Joined: Jun 2016 From: Maine Posts: 9 Thanks: 1 Math Focus: Enjoyed algebra for its utility Exponent Property question How do you get $\displaystyle (a^{n})^{1 \over m}$ as the final product? $\displaystyle a^{n \over m} = (a^{1 \over m})^{n}=(a^{n})^{1 \over m}$
June 18th, 2016, 08:01 AM   #2
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Quote:
 Originally Posted by cold4betbluff How do you get $\displaystyle (a^{n})^{1 \over m}$ as the final product? $\displaystyle a^{n \over m} = (a^{1 \over m})^{n}=(a^{n})^{1 \over m}$
$\dfrac{n}{m} = \dfrac{1}{m} \cdot n = n \cdot \dfrac{1}{m}$

Fairly basic property of multiplication ... where does the confusion lie?

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