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June 17th, 2016, 09:19 AM   #1
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Binomial Factors

Hello, I have a problem (shown below), am I suppose to take out the (3x-4) first? If so, will that be to the left and everything else on the right-hand side?

5(3x-4)² - 8(3x-4)(5x-1)
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June 17th, 2016, 09:41 AM   #2
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Yes, since there is a "3x- 4" in both parts, you can use the "distributive law", (ab+ ac)= a(b+ c), to get (3x- 4)[5(3x- 4)+ 8(5x- 1)]= (3x- 4)(15x- 20+ 40x- 8]= (3x- 4)(55x- 28). (As for "left and right", if that is what you are asking about, it doesn't matter. You could also write (55x- 28)(3x- 4).)
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Last edited by greg1313; June 17th, 2016 at 09:47 AM.
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June 17th, 2016, 09:52 AM   #3
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5(3x - 4)² - 8(3x - 4)(5x - 1)

= (3x - 4)[5(3x - 4) - 8(5x - 1)]

= (3x - 4)(15x - 20 - 40x + 8)

= (3x - 4)(-25x - 12)

= -(3x - 4)(25x + 12)

= (4 - 3x)(25x + 12)
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June 17th, 2016, 12:57 PM   #4
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Wow, Okay, really good answers from both. Thanks for the help it makes a lot more sense now!
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