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 June 17th, 2016, 09:19 AM #1 Newbie   Joined: Jun 2016 From: United States Posts: 10 Thanks: 1 Binomial Factors Hello, I have a problem (shown below), am I suppose to take out the (3x-4) first? If so, will that be to the left and everything else on the right-hand side? 5(3x-4)² - 8(3x-4)(5x-1)
 June 17th, 2016, 09:41 AM #2 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 Yes, since there is a "3x- 4" in both parts, you can use the "distributive law", (ab+ ac)= a(b+ c), to get (3x- 4)[5(3x- 4)+ 8(5x- 1)]= (3x- 4)(15x- 20+ 40x- 8]= (3x- 4)(55x- 28). (As for "left and right", if that is what you are asking about, it doesn't matter. You could also write (55x- 28)(3x- 4).) Thanks from Taco Last edited by greg1313; June 17th, 2016 at 09:47 AM.
 June 17th, 2016, 09:52 AM #3 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,934 Thanks: 1128 Math Focus: Elementary mathematics and beyond 5(3x - 4)² - 8(3x - 4)(5x - 1) = (3x - 4)[5(3x - 4) - 8(5x - 1)] = (3x - 4)(15x - 20 - 40x + 8) = (3x - 4)(-25x - 12) = -(3x - 4)(25x + 12) = (4 - 3x)(25x + 12) Thanks from Taco
 June 17th, 2016, 12:57 PM #4 Newbie   Joined: Jun 2016 From: United States Posts: 10 Thanks: 1 Wow, Okay, really good answers from both. Thanks for the help it makes a lot more sense now!

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