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June 6th, 2016, 10:12 AM   #1
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Confused with quadratic

I am a college student reviewing an algebra problem. It appears that there might be a mistake in the problem, but normally I am just missing a step. This isn't homework, just review. What I am having problems with is one step in a quadratic eq. that has me dividing 6r^2-48r-54=0 by 6, and it ends up as r^2-8r-9=0. Why can the zero stay as it is? Is there a skipped step? Thanx - Chocolatepi
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June 6th, 2016, 10:29 AM   #2
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Originally Posted by chocolatepi View Post
I am a college student reviewing an algebra problem. It appears that there might be a mistake in the problem, but normally I am just missing a step. This isn't homework, just review. What I am having problems with is one step in a quadratic eq. that has me dividing 6r^2-48r-54=0 by 6, and it ends up as r^2-8r-9=0. Why can the zero stay as it is? Is there a skipped step? Thanx - Chocolatepi
$\displaystyle \frac{0}{6} = 0$.
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June 6th, 2016, 11:18 AM   #3
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Can't believe I missed that! Thanx! - Chocolatepi
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June 6th, 2016, 11:38 AM   #4
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Can't believe I missed that! Thanx! - Chocolatepi
Look at it on the bright side: you'll never miss that again
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June 6th, 2016, 03:42 PM   #5
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Look at it on the bright side: you'll never miss that again
Good ole Denis, bringing out the good in everything.
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