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May 25th, 2016, 11:08 AM  #1 
Newbie Joined: May 2016 From: Uk Posts: 2 Thanks: 0  Help: Point between a straight line
Looking for some help in solving the following problem (Q4),using the method shown. The answer they give at the back of the book is 4 and  4. I, however cannot seem to get this?

May 25th, 2016, 11:18 AM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,785 Thanks: 1434  $(6p)^2 + [2p(3)]^2 = \color{red}{(5\sqrt{5})^2}$ $(p^2  12p + 36) + (4p^2+12p+9) = \color{red}{125}$ $5p^2 + 45 = 125$ $p^2 + 9 = 25$ $p^216=0$ $(p4)(p+4) = 0$ $p = \pm 4$ Last edited by skeeter; May 25th, 2016 at 11:24 AM. 
May 25th, 2016, 11:33 AM  #3 
Newbie Joined: May 2016 From: Uk Posts: 2 Thanks: 0 
Awesome thanks. But how did you get from. 5p^2+45=125 to p^2 + 9= 25. EDIT: Ah found it divide the whole lot by 5. thanks for the solution been scratching my head about it all afternoon.
Last edited by Elliot11; May 25th, 2016 at 11:38 AM. 

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