My Math Forum Help: Point between a straight line

 Algebra Pre-Algebra and Basic Algebra Math Forum

May 25th, 2016, 10:08 AM   #1
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Joined: May 2016
From: Uk

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Help: Point between a straight line

Looking for some help in solving the following problem (Q4),using the method shown. The answer they give at the back of the book is 4 and - 4. I, however cannot seem to get this?
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 May 25th, 2016, 10:18 AM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,837 Thanks: 1479 $(6-p)^2 + [2p-(-3)]^2 = \color{red}{(5\sqrt{5})^2}$ $(p^2 - 12p + 36) + (4p^2+12p+9) = \color{red}{125}$ $5p^2 + 45 = 125$ $p^2 + 9 = 25$ $p^2-16=0$ $(p-4)(p+4) = 0$ $p = \pm 4$ Last edited by skeeter; May 25th, 2016 at 10:24 AM.
 May 25th, 2016, 10:33 AM #3 Newbie   Joined: May 2016 From: Uk Posts: 2 Thanks: 0 Awesome thanks. But how did you get from. 5p^2+45=125 to p^2 + 9= 25. EDIT: Ah found it divide the whole lot by 5. thanks for the solution been scratching my head about it all afternoon. Last edited by Elliot11; May 25th, 2016 at 10:38 AM.

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