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May 8th, 2016, 10:29 AM   #1
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Integer ordered pair

Total number of integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$
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May 8th, 2016, 01:19 PM   #2
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Clarify question. Integer ordered pair?
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May 8th, 2016, 06:02 PM   #3
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5! = 120. I'm assuming "integer ordered pair" just means that m and n must be integers, which is normally all we deal with when working with permutations and combinations.
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May 10th, 2016, 07:18 PM   #4
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Quote:
Originally Posted by panky View Post
Total number of positive integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$
As i have tried Here $\displaystyle \displaystyle \binom{120}{1} = \binom{120}{119} = 120$

So we get two positive integer ordered pair $\displaystyle (m,n) = (120,1),(120,119)$

But I did not understand how can i calculate other Positive integer ordered pair

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