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 May 8th, 2016, 10:29 AM #1 Senior Member   Joined: Jul 2011 Posts: 405 Thanks: 16 Integer ordered pair Total number of integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$ May 8th, 2016, 01:19 PM #2 Global Moderator   Joined: May 2007 Posts: 6,834 Thanks: 733 Clarify question. Integer ordered pair? May 8th, 2016, 06:02 PM #3 Senior Member   Joined: Oct 2013 From: New York, USA Posts: 673 Thanks: 88 5! = 120. I'm assuming "integer ordered pair" just means that m and n must be integers, which is normally all we deal with when working with permutations and combinations. Thanks from panky May 10th, 2016, 07:18 PM   #4
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Quote:
 Originally Posted by panky Total number of positive integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$
As i have tried Here $\displaystyle \displaystyle \binom{120}{1} = \binom{120}{119} = 120$

So we get two positive integer ordered pair $\displaystyle (m,n) = (120,1),(120,119)$

But I did not understand how can i calculate other Positive integer ordered pair

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