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May 8th, 2016, 10:29 AM  #1 
Senior Member Joined: Jul 2011 Posts: 405 Thanks: 16  Integer ordered pair
Total number of integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$

May 8th, 2016, 01:19 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,709 Thanks: 675 
Clarify question. Integer ordered pair?

May 8th, 2016, 06:02 PM  #3 
Senior Member Joined: Oct 2013 From: New York, USA Posts: 637 Thanks: 85 
5! = 120. I'm assuming "integer ordered pair" just means that m and n must be integers, which is normally all we deal with when working with permutations and combinations.

May 10th, 2016, 07:18 PM  #4  
Senior Member Joined: Jul 2011 Posts: 405 Thanks: 16  Quote:
So we get two positive integer ordered pair $\displaystyle (m,n) = (120,1),(120,119)$ But I did not understand how can i calculate other Positive integer ordered pair Thanks  

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