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panky May 8th, 2016 10:29 AM

Integer ordered pair
 
Total number of integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$

mathman May 8th, 2016 01:19 PM

Clarify question. Integer ordered pair?

EvanJ May 8th, 2016 06:02 PM

5! = 120. I'm assuming "integer ordered pair" just means that m and n must be integers, which is normally all we deal with when working with permutations and combinations.

panky May 10th, 2016 07:18 PM

Quote:

Originally Posted by panky (Post 535003)
Total number of positive integer ordered pair $\displaystyle (m,n)$ in $\displaystyle \displaystyle \binom{m}{n} = 120$

As i have tried Here $\displaystyle \displaystyle \binom{120}{1} = \binom{120}{119} = 120$

So we get two positive integer ordered pair $\displaystyle (m,n) = (120,1),(120,119)$

But I did not understand how can i calculate other Positive integer ordered pair

Thanks


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