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 panky May 8th, 2016 10:29 AM

Integer ordered pair

Total number of integer ordered pair \$\displaystyle (m,n)\$ in \$\displaystyle \displaystyle \binom{m}{n} = 120\$

 mathman May 8th, 2016 01:19 PM

Clarify question. Integer ordered pair?

 EvanJ May 8th, 2016 06:02 PM

5! = 120. I'm assuming "integer ordered pair" just means that m and n must be integers, which is normally all we deal with when working with permutations and combinations.

 panky May 10th, 2016 07:18 PM

Quote:
 Originally Posted by panky (Post 535003) Total number of positive integer ordered pair \$\displaystyle (m,n)\$ in \$\displaystyle \displaystyle \binom{m}{n} = 120\$
As i have tried Here \$\displaystyle \displaystyle \binom{120}{1} = \binom{120}{119} = 120\$

So we get two positive integer ordered pair \$\displaystyle (m,n) = (120,1),(120,119)\$

But I did not understand how can i calculate other Positive integer ordered pair

Thanks

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