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April 28th, 2016, 05:09 PM   #1
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can someone explain Factoring Trinomials in the Form x^2+bx+c

Before I was looking at it as Dividing it as 5 for each of these.
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April 28th, 2016, 05:27 PM   #2
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first rule of factoring ... pull out any common factors

$5(x^2-7x+10)$

then factor the trinomial

$5(x-2)(x-5)$
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April 28th, 2016, 05:34 PM   #3
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$\displaystyle 5(x^2-7x+10)$

Now, what two numbers have a sum of $-7$ and are equal to $10$ when multiplied together?
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