My Math Forum can someone explain Factoring Trinomials in the Form x^2+bx+c
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April 28th, 2016, 04:09 PM   #1
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can someone explain Factoring Trinomials in the Form x^2+bx+c

Before I was looking at it as Dividing it as 5 for each of these.
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 April 28th, 2016, 04:27 PM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 2,982 Thanks: 1575 first rule of factoring ... pull out any common factors $5(x^2-7x+10)$ then factor the trinomial $5(x-2)(x-5)$ Thanks from GIjoefan1976
 April 28th, 2016, 04:34 PM #3 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,950 Thanks: 1141 Math Focus: Elementary mathematics and beyond $\displaystyle 5(x^2-7x+10)$ Now, what two numbers have a sum of $-7$ and are equal to $10$ when multiplied together? Thanks from GIjoefan1976

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