My Math Forum Solving using radians

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 December 29th, 2012, 01:50 PM #1 Newbie   Joined: Dec 2012 Posts: 1 Thanks: 0 Solving using radians My question is: cot(theta) + sqrt(3) = 0. I am required to find all solutions and answer in radians in term of pi. I have no idea where to begin. Any help would be appreciated!
December 29th, 2012, 03:26 PM   #2
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Hello, bentroy743!

Quote:
 $\text{Find all solutions (in radians): }\:\cot\theta\,+\,\sqrt{3}\:=\:0$

$\text{W\!e have: }\:\cot\theta \:=\:-\frac{\sqrt{3}}{1} \:=\:\frac{adj}{opp}$

$\text{Cotangent is negative in Quadrants 2 and 4.}$

$\begin{Bmatrix}\text{In Quadrant 2: } & \theta &=& \frac{5\pi}{6}\,+\,2\pi n \\ \\ \\
\text{In Quadrant 4: } & \theta &=& -\frac{\pi}{6}\,+\,2\pi n \end{Bmatrix}\;\text{ for any integer }n.$

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