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March 8th, 2016, 04:15 PM  #1 
Newbie Joined: Mar 2016 From: India Posts: 5 Thanks: 0  Factor ((Lm)/2)xÂ²  ((L+m)/2) x + m =0
I need the steps too Thanks in Advance 
March 8th, 2016, 04:42 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,924 Thanks: 1521 
quadratic formula ... $a=\dfrac{Lm}{2}$, $b = \dfrac{L+m}{2}$, $c=m$ $b^24ac = \dfrac{(L+m)^2}{4}  2m(Lm) = \dfrac{(L3m)^2}{4}$ $x = \dfrac{\frac{L+m}{2} \pm \frac{L3m}{2}}{Lm} = 1 \text{ or } \dfrac{2m}{Lm}$ 
March 8th, 2016, 04:54 PM  #3 
Newbie Joined: Mar 2016 From: India Posts: 5 Thanks: 0 
got it Thanks
Last edited by Mukunth; March 8th, 2016 at 04:57 PM. Reason: Got the Answer 
March 9th, 2016, 12:08 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 20,641 Thanks: 2084 
By inspection, x = 1 satisfies the equation, so its lefthand side equals (x  1)((L  m)x  2m))/2. 

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factor, lm or 2xÂ², m or 2 
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