My Math Forum Factor ((L-m)/2)xÂ² - ((L+m)/2) x + m =0

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 March 8th, 2016, 04:15 PM #1 Newbie   Joined: Mar 2016 From: India Posts: 5 Thanks: 0 Factor ((L-m)/2)xÂ² - ((L+m)/2) x + m =0 I need the steps too Thanks in Advance
 March 8th, 2016, 04:42 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,770 Thanks: 1424 quadratic formula ... $a=\dfrac{L-m}{2}$, $b = -\dfrac{L+m}{2}$, $c=m$ $b^2-4ac = \dfrac{(L+m)^2}{4} - 2m(L-m) = \dfrac{(L-3m)^2}{4}$ $x = \dfrac{\frac{L+m}{2} \pm \frac{L-3m}{2}}{L-m} = 1 \text{ or } \dfrac{2m}{L-m}$ Thanks from topsquark and Mukunth
 March 8th, 2016, 04:54 PM #3 Newbie   Joined: Mar 2016 From: India Posts: 5 Thanks: 0 got it Thanks Last edited by Mukunth; March 8th, 2016 at 04:57 PM. Reason: Got the Answer
 March 9th, 2016, 12:08 AM #4 Global Moderator   Joined: Dec 2006 Posts: 19,704 Thanks: 1804 By inspection, x = 1 satisfies the equation, so its left-hand side equals (x - 1)((L - m)x - 2m))/2.

 Tags factor, lm or 2xÂ², m or 2

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# (l-m)x² - (l m)x 2m = 0

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