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March 8th, 2016, 05:15 PM   #1
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Question Factor ((L-m)/2)x² - ((L+m)/2) x + m =0

I need the steps too

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March 8th, 2016, 05:42 PM   #2
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quadratic formula ...

$a=\dfrac{L-m}{2}$, $b = -\dfrac{L+m}{2}$, $c=m$

$b^2-4ac = \dfrac{(L+m)^2}{4} - 2m(L-m) = \dfrac{(L-3m)^2}{4}$

$x = \dfrac{\frac{L+m}{2} \pm \frac{L-3m}{2}}{L-m} = 1 \text{ or } \dfrac{2m}{L-m}$
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March 8th, 2016, 05:54 PM   #3
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got it Thanks

Last edited by Mukunth; March 8th, 2016 at 05:57 PM. Reason: Got the Answer
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March 9th, 2016, 01:08 AM   #4
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By inspection, x = 1 satisfies the equation,
so its left-hand side equals (x - 1)((L - m)x - 2m))/2.
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