My Math Forum Algebra Word Problem

 Algebra Pre-Algebra and Basic Algebra Math Forum

 March 2nd, 2016, 05:10 PM #1 Member   Joined: Mar 2015 From: KY Posts: 35 Thanks: 1 Algebra Word Problem Can anyone help with my son's problem above? Last edited by skipjack; March 2nd, 2016 at 05:30 PM.
March 2nd, 2016, 05:56 PM   #2
Global Moderator

Joined: Dec 2006

Posts: 20,942
Thanks: 2210

Quote:
 Originally Posted by scsims A box of 60 pens contains pens of four different colors. The box contains five times as many red pens as black pens, and four more black pens than green pens. The number of red, green, and black pens combined is three times the number of blue pens. How many pens of each color are in the box?
If there are n green pens, there are n+4 black pens and 5n+20 red pens,
so the number of blue pens is (n + n+4 + 5n+20)/3, i.e. 7n/3 + 8.

As the blue pens are outnumbered 3:1 by the others, there are 15 blue pens (and 45 others).

Hence 7n/3 + 8 = 15, and so n = 3.

There are therefore 3 green, 7 black, 35 red and 15 blue pens in the box.

Also answered here many years ago.

 Tags algebra, problem, word

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post apparentlynothing Algebra 4 January 21st, 2013 06:14 PM Hansmatta Algebra 1 October 28th, 2011 01:28 AM Stang2005 Algebra 10 September 2nd, 2011 07:40 AM sssmath Algebra 10 May 14th, 2009 11:35 AM mvanant123 Algebra 3 November 5th, 2008 11:23 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top