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March 2nd, 2016, 05:10 PM  #1 
Member Joined: Mar 2015 From: KY Posts: 35 Thanks: 1  Algebra Word Problem Can anyone help with my son's problem above? Last edited by skipjack; March 2nd, 2016 at 05:30 PM. 
March 2nd, 2016, 05:56 PM  #2  
Global Moderator Joined: Dec 2006 Posts: 20,469 Thanks: 2038  Quote:
so the number of blue pens is (n + n+4 + 5n+20)/3, i.e. 7n/3 + 8. As the blue pens are outnumbered 3:1 by the others, there are 15 blue pens (and 45 others). Hence 7n/3 + 8 = 15, and so n = 3. There are therefore 3 green, 7 black, 35 red and 15 blue pens in the box. Also answered here many years ago.  

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