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February 29th, 2016, 02:11 PM   #11
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Originally Posted by pelluzi View Post
Hi there,


I have no idea how to solve this equation:

$\displaystyle x! = 2^x + 8$



Cheers!
Luis P.
There is another issue which has not been mentioned yet. (As if an analytical solution isn't impossible enough to find!) Unless you specify otherwise it may be that x isn't a whole number. x! can be defined for any non-negative real number and you have to include such a possibility in a general solution. Fortunately we don't have that particular problem here.

-Dan
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February 29th, 2016, 02:35 PM   #12
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There is another issue which has not been mentioned yet. (As if an analytical solution isn't impossible enough to find!) Unless you specify otherwise it may be that x isn't a whole number. x! can be defined for any non-negative real number and you have to include such a possibility in a general solution. Fortunately we don't have that particular problem here.

-Dan
Yeap, I find out wolframalpha for questions like that
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February 29th, 2016, 02:35 PM   #13
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Wow, skeeter! That is really useful!

xxx
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