One number is four more than five times another. If their sum is decreased by six.... One number is four more than five times another. If their sum is decreased by six, the result is ten. Find the numbers. I tried to write the equation from reading this. Is this anywhere near close? x+4+5x6=10 Thanks. 
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Then test it yourself by substituting... 
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and both this time, and last time I can get the first number being 2. yet then I go 2 plus 4 =6 * 5 is 30 6 =24 so not yet figuring out why it is not working for me. 
First of all, you have two numbers. Call them $x$ and $y$. The information gives you two equations relating $x$, $y$ and numbers you are given. See if you can build those equations from the text of the question. 
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"One number is four more than five times another." other number= 5*2 + 4 = 14 ; OK? "If their sum is decreased by six, the result is ten." sum = 2 + 14 = 16 16  6 = 10 : Bingo! You're correct:cool: 
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Other number is 4+5x Quote:
The only difference is brackets. Continue. 
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Yet if i did it this way it confused me too as i would have gone and got 36x24=10 ? 
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There's no multiplication there; just remove the brackets: x + 4 + 5x  6 = 10 6x = 10  4 + 6 6x = 12 x = 2 
If you write that you have two numbers $x$ and $y$, then you get two equations $y = 4+5x$ and $x+y  6= 10$. If you have learned how to solve simultaneous equations, this is not too difficult to solve (indeed one approach gives you exactly the equation that Denis was working you through. The important thing is to be able to build the equations. To understand what the sentences tell you and be confident that you have written it down correctly. The rest is relatively simple algebra. 
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