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 Algebra Pre-Algebra and Basic Algebra Math Forum

 February 16th, 2016, 04:57 AM #1 Newbie   Joined: Feb 2016 From: india Posts: 7 Thanks: 0 8w - 3 = 11 The question is "solve 8w - 3 = 11" help me out please. and another one is "solve 3(y - 4) = 9" February 16th, 2016, 04:59 AM #2 Senior Member   Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3 If you don't know what to do after this then math is not for you. February 16th, 2016, 05:04 AM   #3
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Quote:
 Originally Posted by Monox D. I-Fly 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3 If you don't know what to do after this then math is not for you.
what about another one is "solve 3(y - 4) = 9" friend February 16th, 2016, 05:14 AM   #4
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Quote:
 Originally Posted by r3v what about another one is "solve 3(y - 4) = 9" friend
3(y-4) = 9
y-4 = 9/3
y-4 = 3
y = 3+4
y = 7 February 16th, 2016, 05:22 AM   #5
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Quote:
 Originally Posted by r3v what about another one is "solve 3(y - 4) = 9" friend
Huh? When did you wrote it? I didn't see it. February 16th, 2016, 05:56 AM   #6
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Quote:
 Originally Posted by Monox D. I-Fly 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3
OP posted this ...

Quote:
 8w - 3 = 11 The question is "solve 8w - 3 = 11" help me out please.
Was there an unseen edit? February 16th, 2016, 06:52 AM #7 Senior Member   Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry Oops, sorry. 8w - 3 = 11 8w - 3 + 3 = 11 + 3 8w = 14 Can you continue? February 16th, 2016, 11:57 AM #8 Senior Member   Joined: Dec 2015 From: holland Posts: 162 Thanks: 37 Math Focus: tetration 8w-3=11 8w=11+3 w=14/8 =1+3/4 3(y-4)=9 y-4=3 y=7 Last edited by manus; February 16th, 2016 at 12:12 PM. Reason: forgot something February 16th, 2016, 12:12 PM #9 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 You can, of course, reduce the fraction 14/8 to 7/4 and, if you wish, reduce that to the "mixed fraction" 1 and 3/4. r3v, all of these problems can be solved by "undoing" what has been done to the unknown value. In the first, 8- w= 11, we can think "on the right side, 8 has been added to -w. I can undo that by subtracting 8". And, of course, whatever we do to one side, we must do to the other. Doing that, we have -w= 11- 8= 3. Now, the only problem is that we have "-w" when we want "w". Thinking of that as "-1 times w", we undo it by dividing both sides by -1: -w/-1= 3/-1 so w= -3. In the second, 3(y- 4)= 9, we immediately see that the parentheses on the left side are multiplied by 3. We undo that by dividing both sides by 3: y- 4= 9/3= 3. Now, the only reason we do not have y by itself is that 4 is subtracted from it. We can undo that by adding 4 to both sides: y= 3+ 4= 7. Thanks from greg1313 February 16th, 2016, 04:31 PM   #10
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Quote:
 Originally Posted by skeeter Was there an unseen edit?
An edit is unseen if it's done very soon after the original post. Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode

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