My Math Forum 8w - 3 = 11

 Algebra Pre-Algebra and Basic Algebra Math Forum

 February 16th, 2016, 04:57 AM #1 Newbie   Joined: Feb 2016 From: india Posts: 7 Thanks: 0 8w - 3 = 11 The question is "solve 8w - 3 = 11" help me out please. and another one is "solve 3(y - 4) = 9"
 February 16th, 2016, 04:59 AM #2 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3 If you don't know what to do after this then math is not for you.
February 16th, 2016, 05:04 AM   #3
Newbie

Joined: Feb 2016
From: india

Posts: 7
Thanks: 0

Quote:
 Originally Posted by Monox D. I-Fly 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3 If you don't know what to do after this then math is not for you.
what about another one is "solve 3(y - 4) = 9" friend

February 16th, 2016, 05:14 AM   #4
Senior Member

Joined: Dec 2012
From: Hong Kong

Posts: 853
Thanks: 311

Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics
Quote:
 Originally Posted by r3v what about another one is "solve 3(y - 4) = 9" friend
3(y-4) = 9
y-4 = 9/3
y-4 = 3
y = 3+4
y = 7

February 16th, 2016, 05:22 AM   #5
Senior Member

Joined: Nov 2010
From: Indonesia

Posts: 2,001
Thanks: 132

Math Focus: Trigonometry
Quote:
 Originally Posted by r3v what about another one is "solve 3(y - 4) = 9" friend
Huh? When did you wrote it? I didn't see it.

February 16th, 2016, 05:56 AM   #6
Math Team

Joined: Jul 2011
From: Texas

Posts: 3,044
Thanks: 1627

Quote:
 Originally Posted by Monox D. I-Fly 8 - w = 11 8 - w - 8 = 11 - 8 -w = 3
OP posted this ...

Quote:
 8w - 3 = 11 The question is "solve 8w - 3 = 11" help me out please.
Was there an unseen edit?

 February 16th, 2016, 06:52 AM #7 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry Oops, sorry. 8w - 3 = 11 8w - 3 + 3 = 11 + 3 8w = 14 Can you continue?
 February 16th, 2016, 11:57 AM #8 Senior Member   Joined: Dec 2015 From: holland Posts: 162 Thanks: 37 Math Focus: tetration 8w-3=11 8w=11+3 w=14/8 =1+3/4 3(y-4)=9 y-4=3 y=7 Last edited by manus; February 16th, 2016 at 12:12 PM. Reason: forgot something
 February 16th, 2016, 12:12 PM #9 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 You can, of course, reduce the fraction 14/8 to 7/4 and, if you wish, reduce that to the "mixed fraction" 1 and 3/4. r3v, all of these problems can be solved by "undoing" what has been done to the unknown value. In the first, 8- w= 11, we can think "on the right side, 8 has been added to -w. I can undo that by subtracting 8". And, of course, whatever we do to one side, we must do to the other. Doing that, we have -w= 11- 8= 3. Now, the only problem is that we have "-w" when we want "w". Thinking of that as "-1 times w", we undo it by dividing both sides by -1: -w/-1= 3/-1 so w= -3. In the second, 3(y- 4)= 9, we immediately see that the parentheses on the left side are multiplied by 3. We undo that by dividing both sides by 3: y- 4= 9/3= 3. Now, the only reason we do not have y by itself is that 4 is subtracted from it. We can undo that by adding 4 to both sides: y= 3+ 4= 7. Thanks from greg1313
February 16th, 2016, 04:31 PM   #10
Global Moderator

Joined: Dec 2006

Posts: 21,036
Thanks: 2273

Quote:
 Originally Posted by skeeter Was there an unseen edit?
An edit is unseen if it's done very soon after the original post.

 Thread Tools Display Modes Linear Mode

 Contact - Home - Forums - Cryptocurrency Forum - Top