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 February 15th, 2016, 06:52 AM #1 Newbie   Joined: Feb 2016 From: india Posts: 7 Thanks: 0 solve this equation - confused 9x + 3 = 7x + 10 This seems so simple, but I forgot how to do it. Please help!
 February 15th, 2016, 07:16 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra The idea is to remove all the $x$s from one side of the equation and everything else from the other. We do it one step at a time, remembering that we must do the same thing to both sides of the equation. \begin{aligned} && 9x+ 3 &= 7x+10 \\ &\text{first I will remove the 7x from the right by subtracting it} & 9x+3-7x &= 7x+10-7x \\ &\text{and group the terms} & \cancelto{2x}{(9x - 7x)} + 3 &= \cancelto{0}{(7x - 7x)}+10 \\ && 2x + 3 &= 10 \\ &\text{now I will remove the constant 3 from the left by subtracting it} & 2x+3-3 &= 10 -3 \\ &\text{and group the terms} & 2x+\cancelto{0}{(3-3)} &= \cancelto{7}{(10-3)} \\ && 2x &= 7 \\ &\text{and finally, I will remove the coefficient 2 from the left by dividing it} & {2x \over 2} &= \frac72 \\ &\text{and group the terms} & \cancelto{1}{\frac22}x &= \frac72 \\ && 1x &= \frac72 \\ && x &= \frac72 \end{aligned} Thanks from topsquark

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