My Math Forum length times width and getting a new equation for area?

 Algebra Pre-Algebra and Basic Algebra Math Forum

 February 13th, 2016, 09:48 AM #1 Newbie   Joined: May 2010 Posts: 6 Thanks: 0 length times width and getting a new equation for area? So here's my problem. l = 52 - 2w I need to write an equation for area based on width using the above equation. What am I missing here? Whatever the equation is, I have to enter it into my calculator to see the parabola, get the vertex, etc. I just can't figure out what the equation is I'm supposed to enter. Any info would be appreciated. Thanks!
 February 13th, 2016, 09:50 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra $A=lw$, and $l=52-2w$, so substitute.
 February 13th, 2016, 10:01 AM #3 Newbie   Joined: May 2010 Posts: 6 Thanks: 0 Thanks. Still confused though! We're using a word problem asking about 52 panels, each 1ft long. The back of a house will close in one side of the patio. The question is: Generalize a model (equation) for calculating the length (l) in terms of the width (w). Hint: work from perimeter: P=2l +2w I'm assuming I'm right with the first part (l = 52 - 2w). But nothing I graph shows a parabola.
 February 13th, 2016, 11:16 AM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond What is the exact problem statement (as worded by your instructor)? Include all given information.

 Tags area, equation, length, times, width

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