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February 11th, 2016, 02:28 PM  #1 
Senior Member Joined: Feb 2016 From: seattle Posts: 354 Thanks: 10  word problem. just not sure how to write words as a formula
One number is three less than four times another. If their sum is increased by six, the result is twentyeight. Find the numbers. The smaller of the numbers is and the larger is . So is that x3+4(y+6)=28 ? Thanks Last edited by skipjack; February 13th, 2016 at 08:28 PM. 
February 11th, 2016, 02:42 PM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,595 Thanks: 1285 
x = one number y = another number Quote:
Quote:
solve the system of two equations  
February 11th, 2016, 03:27 PM  #3  
Senior Member Joined: Jul 2014 From: भारत Posts: 1,178 Thanks: 230  Quote:
Let the smaller number be $x$. The bigger number is $4x3$. According to the question, $6+ {\large[} x + (4x3) {\large]} = 28$ Solving for $x$, we get $x=5$ So, the smaller number is 5. The bigger number is $4x3=17$. Hence the numbers are 5 and 17. Last edited by skipjack; February 13th, 2016 at 08:27 PM.  
February 13th, 2016, 10:14 AM  #4 
Senior Member Joined: Feb 2016 From: seattle Posts: 354 Thanks: 10 
Thanks to you both, it still confuses me, I will just have to remember once solving for x I need to then redo the equation once I have figured out what x was Prakhar very impressed by your being able to do it with your one variable formula! 
February 13th, 2016, 07:59 PM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 10,075 Thanks: 681  

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