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December 16th, 2012, 03:51 AM   #1
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Complex numbers

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 December 16th, 2012, 05:29 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,935 Thanks: 2209 Can you evaluate (a) the numerator of the first term, (b) the denominator of the first term, or (c) the second term?
 December 16th, 2012, 08:11 AM #3 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Complex numbers I don't know how to do this..(
 December 16th, 2012, 08:30 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,935 Thanks: 2209 (a)  Can you evaluate (1 + 2i) - (2 - i)?
 December 16th, 2012, 08:45 AM #5 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Complex numbers Yes, I get 3i-1
 December 16th, 2012, 01:03 PM #6 Global Moderator   Joined: Dec 2006 Posts: 20,935 Thanks: 2209 That is correct. (b)  Can you evaluate (1 + 2i)²? (In doing so, simplify the result by using the fact that i² = -1.) (c)  Bearing in mind that i² = -1, what is the value of i^2013 = (i^2012)i?

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