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December 16th, 2012, 02:35 AM   #11
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Re: Complex numbers;

Not quite. Your 2nd and 3rd lines should be:

= 2i(2i)i+2-2i
= 4i^2 i +2-2i

So what do you wind up with?
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December 16th, 2012, 02:39 AM   #12
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Re: Complex numbers;

This: 2-6i
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December 16th, 2012, 02:48 AM   #13
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Re: Complex numbers;

Yes, that's correct. Your textbook may write the result as .
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December 16th, 2012, 02:53 AM   #14
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Re: Complex numbers

My text book has written the answer as 0 (zero); maybe them have made mistakes..
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December 16th, 2012, 02:58 AM   #15
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Re: Complex numbers

Presumably, as 0 is not the result.
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