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 December 15th, 2012, 11:35 PM #11 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers I dont know this step( can you help more?
 December 15th, 2012, 11:39 PM #12 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Help complex numbers $-$$1+\frac{1}{5}$$-$$2+\frac{2}{5}$$i$ Now, combine the numbers within the parentheses.
 December 16th, 2012, 12:00 AM #13 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers I get this: -6/5 -12/5i
 December 16th, 2012, 12:14 AM #14 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers Are it right?
 December 16th, 2012, 12:29 AM #15 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Help complex numbers Yes, that's correct!
 December 16th, 2012, 12:37 AM #16 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers The answer on the book are : -6/5 * (1+2i) Maybe tha author have make mistakes.
 December 16th, 2012, 12:45 AM #17 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers Im not sure but on the text the answer is : -6/5 * (1+2i)
 December 16th, 2012, 12:57 AM #18 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Help complex numbers That is equivalent to your answer, just factor -6/5 out. I am used to the result being given in the form a + bi.
 December 16th, 2012, 01:01 AM #19 Newbie   Joined: Dec 2012 Posts: 28 Thanks: 0 Re: Help complex numbers So both of them are correct?
 December 16th, 2012, 01:09 AM #20 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Help complex numbers Yes, they are just different ways to write the same thing. Observe that: $-\frac{6}{5}(1+2i)=-\frac{6}{5}-\frac{12}{5}i$

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